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An organic compound having molecular mass 60 is found to contain C = 20%, H = 6.67% and N = 46.67% while rest is oxygen. On heating it gives NH3 alongwith a solid residue.
The solid residue give violet colour with alkaline copper sulphate solution. The compound is
- a)CH3CH2CONH2
- b)(NH2)2 CO
- c)CH3CONH2
- d)CH3NCO
Correct answer is option 'B'. Can you explain this answer?
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Most Upvoted Answer
An organic compound having molecular mass 60 is found to contain C = 2...
Given: C=20% , H=6.67% and N=46.67%
Therefore O= 100-(20 + 6.67 + 46.67) = 26.66%
Mol mass is given at 60
Wt. of each element = C= 20% = 12 i.e 1 atom of C as at mass of C=12
H = 6.67% = 4 i.e. 4 atoms of H
N = 46.67% = 28 i.e. 2 atoms of N
O = 26.66% = 15.96 = 1 atom of O
Mol formula = CH4N2O =
As the copper sulphate changes color the test implies presence of peptide bond. -CO-NH-
Also, the loss of NH3 on heating also justifies this fact
Hence the structure should be NH2-CO-NH2
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Community Answer
An organic compound having molecular mass 60 is found to contain C = 2...
Given information:
- Molecular mass of the compound = 60
- Percentage composition: C = 20%, H = 6.67%, N = 46.67%
- Rest of the compound is oxygen
- On heating, it gives NH3 and a solid residue
- The solid residue gives a violet color with alkaline copper sulphate solution
Solution:
Step 1: Finding the empirical formula
To determine the empirical formula, we need to find the ratio of the elements present in the compound.
Given:
- Percentage composition of C = 20%
- Percentage composition of H = 6.67%
- Percentage composition of N = 46.67%
Assuming:
- 100g of the compound
Calculating the masses:
- Mass of C in 100g = 20g
- Mass of H in 100g = 6.67g
- Mass of N in 100g = 46.67g
- Mass of O in 100g = (100 - 20 - 6.67 - 46.67)g = 26.66g
Calculating the moles:
- Moles of C = 20g / 12g/mol = 1.67 mol
- Moles of H = 6.67g / 1g/mol = 6.67 mol
- Moles of N = 46.67g / 14g/mol = 3.33 mol
- Moles of O = 26.66g / 16g/mol = 1.67 mol
Dividing the moles by the smallest number of moles:
- Moles of C = 1.67 mol / 1.67 mol = 1
- Moles of H = 6.67 mol / 1.67 mol = 4
- Moles of N = 3.33 mol / 1.67 mol = 2
- Moles of O = 1.67 mol / 1.67 mol = 1
The empirical formula:
C1H4N2O1 = CH4N2O
Step 2: Determining the molecular formula
To find the molecular formula, we need to know the molecular mass of the compound.
Given:
- Molecular mass of the compound = 60
Calculating the empirical formula mass:
- Empirical formula mass = (1 * 12) + (4 * 1) + (2 * 14) + (1 * 16) = 32
Calculating the factor:
- Factor = Molecular formula mass / Empirical formula mass
- Factor = 60 / 32 = 1.875
Multiplying the subscripts of the empirical formula by the factor:
- Molecular formula = (C1H4N2O1) * 1.875 = C1.875H7.5N3.75O1.875
Simplifying the molecular formula:
- C1.875H7.5N3.75O1.875 ≈ C2H8N4O2
- Molecular mass of the compound = 60
- Percentage composition: C = 20%, H = 6.67%, N = 46.67%
- Rest of the compound is oxygen
- On heating, it gives NH3 and a solid residue
- The solid residue gives a violet color with alkaline copper sulphate solution
Solution:
Step 1: Finding the empirical formula
To determine the empirical formula, we need to find the ratio of the elements present in the compound.
Given:
- Percentage composition of C = 20%
- Percentage composition of H = 6.67%
- Percentage composition of N = 46.67%
Assuming:
- 100g of the compound
Calculating the masses:
- Mass of C in 100g = 20g
- Mass of H in 100g = 6.67g
- Mass of N in 100g = 46.67g
- Mass of O in 100g = (100 - 20 - 6.67 - 46.67)g = 26.66g
Calculating the moles:
- Moles of C = 20g / 12g/mol = 1.67 mol
- Moles of H = 6.67g / 1g/mol = 6.67 mol
- Moles of N = 46.67g / 14g/mol = 3.33 mol
- Moles of O = 26.66g / 16g/mol = 1.67 mol
Dividing the moles by the smallest number of moles:
- Moles of C = 1.67 mol / 1.67 mol = 1
- Moles of H = 6.67 mol / 1.67 mol = 4
- Moles of N = 3.33 mol / 1.67 mol = 2
- Moles of O = 1.67 mol / 1.67 mol = 1
The empirical formula:
C1H4N2O1 = CH4N2O
Step 2: Determining the molecular formula
To find the molecular formula, we need to know the molecular mass of the compound.
Given:
- Molecular mass of the compound = 60
Calculating the empirical formula mass:
- Empirical formula mass = (1 * 12) + (4 * 1) + (2 * 14) + (1 * 16) = 32
Calculating the factor:
- Factor = Molecular formula mass / Empirical formula mass
- Factor = 60 / 32 = 1.875
Multiplying the subscripts of the empirical formula by the factor:
- Molecular formula = (C1H4N2O1) * 1.875 = C1.875H7.5N3.75O1.875
Simplifying the molecular formula:
- C1.875H7.5N3.75O1.875 ≈ C2H8N4O2
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An organic compound having molecular mass 60 is found to contain C = 20%, H = 6.67% and N = 46.67% while rest is oxygen. On heating it gives NH3 alongwith a solid residue.The solid residue give violet colour with alkaline copper sulphate solution. The compound isa)CH3CH2CONH2b)(NH2)2 COc)CH3CONH2d)CH3NCOCorrect answer is option 'B'. Can you explain this answer?
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An organic compound having molecular mass 60 is found to contain C = 20%, H = 6.67% and N = 46.67% while rest is oxygen. On heating it gives NH3 alongwith a solid residue.The solid residue give violet colour with alkaline copper sulphate solution. The compound isa)CH3CH2CONH2b)(NH2)2 COc)CH3CONH2d)CH3NCOCorrect answer is option 'B'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about An organic compound having molecular mass 60 is found to contain C = 20%, H = 6.67% and N = 46.67% while rest is oxygen. On heating it gives NH3 alongwith a solid residue.The solid residue give violet colour with alkaline copper sulphate solution. The compound isa)CH3CH2CONH2b)(NH2)2 COc)CH3CONH2d)CH3NCOCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An organic compound having molecular mass 60 is found to contain C = 20%, H = 6.67% and N = 46.67% while rest is oxygen. On heating it gives NH3 alongwith a solid residue.The solid residue give violet colour with alkaline copper sulphate solution. The compound isa)CH3CH2CONH2b)(NH2)2 COc)CH3CONH2d)CH3NCOCorrect answer is option 'B'. Can you explain this answer?.
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An organic compound having molecular mass 60 is found to contain C = 20%, H = 6.67% and N = 46.67% while rest is oxygen. On heating it gives NH3 alongwith a solid residue.The solid residue give violet colour with alkaline copper sulphate solution. The compound isa)CH3CH2CONH2b)(NH2)2 COc)CH3CONH2d)CH3NCOCorrect answer is option 'B'. Can you explain this answer?, a detailed solution for An organic compound having molecular mass 60 is found to contain C = 20%, H = 6.67% and N = 46.67% while rest is oxygen. On heating it gives NH3 alongwith a solid residue.The solid residue give violet colour with alkaline copper sulphate solution. The compound isa)CH3CH2CONH2b)(NH2)2 COc)CH3CONH2d)CH3NCOCorrect answer is option 'B'. Can you explain this answer? has been provided alongside types of An organic compound having molecular mass 60 is found to contain C = 20%, H = 6.67% and N = 46.67% while rest is oxygen. On heating it gives NH3 alongwith a solid residue.The solid residue give violet colour with alkaline copper sulphate solution. The compound isa)CH3CH2CONH2b)(NH2)2 COc)CH3CONH2d)CH3NCOCorrect answer is option 'B'. Can you explain this answer? theory, EduRev gives you an
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