Mahesh borrowed a certain sum for 2 years at simple interest from Bhim...
**Given Information:**
- Mahesh borrowed a certain sum for 2 years at simple interest from Bhim Mahesh.
- Mahesh borrowed the same sum for 2 years at compound interest from Vishnu.
- At the end of 2 years, Mahesh paid rupees 400 as simple interest.
- At the end of 2 years, Mahesh paid rupees 410 as compound interest.
**To Find:**
- The sum borrowed by Mahesh.
- The rate of interest.
**Solution:**
Let's assume that the principal amount borrowed by Mahesh is 'P' and the rate of interest is 'R'.
**Simple Interest:**
The formula for calculating simple interest is: S.I. = (P * R * T) / 100
where P is the principal amount, R is the rate of interest, and T is the time period.
Given that Mahesh paid rupees 400 as simple interest for 2 years, we can write the equation as:
400 = (P * R * 2) / 100
Simplifying the equation, we get:
2PR = 40000 (Equation 1)
**Compound Interest:**
The formula for calculating compound interest is: C.I. = P(1 + R/100)^T - P
where P is the principal amount, R is the rate of interest, and T is the time period.
Given that Mahesh paid rupees 410 as compound interest for 2 years, we can write the equation as:
410 = P(1 + R/100)^2 - P
Simplifying the equation, we get:
(1 + R/100)^2 = 410/P + 1 (Equation 2)
**Solving Equations 1 and 2:**
We can solve equations 1 and 2 simultaneously to find the value of P and R.
From Equation 1, we have:
2PR = 40000
From Equation 2, we have:
(1 + R/100)^2 = 410/P + 1
Simplifying the second equation, we have:
(1 + R/100)^2 - 1 = 410/P
(1 + R/100)^2 = (410 + P)/P
Taking the square root on both sides, we get:
1 + R/100 = sqrt((410 + P)/P)
R/100 = sqrt((410 + P)/P) - 1
Simplifying further, we have:
R = 100(sqrt((410 + P)/P) - 1)
Now, we can substitute the value of R in Equation 1 to find the value of P.
2P * 100(sqrt((410 + P)/P) - 1) = 40000
Simplifying the equation, we can solve it to find the value of P.
Once we find the value of P, we can substitute it in Equation 1 or Equation 2 to find the value of R.
Therefore, the sum borrowed by Mahesh and the rate of interest can be determined by solving the above equations.
Mahesh borrowed a certain sum for 2 years at simple interest from Bhim...
We know that SI = PTR/100
P = SI * 100/r*t
= 400 * 100 / r * 2
= 20000/R
We know that CI = P(1+r/100)^n - P
= P(1+r/100)^n - 1
410 = 20000/R(1+r/100)^n - 1
410 = 20000/R(10000 + R^2 + 2000R - 10000)/10000
410 = 2/R(R^2 + 200R)
410R = 2(R^2+200R)
2R^2 + 400R - 410R = 0
2R^2 = 10R
Rs =5
P = 20000/5
= 4000.
Sum = 4000, Rate =5%
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