Reactive power is a component of power in AC circuits that does not perform any useful work but is required to establish and maintain the electromagnetic fields in inductive and capacitive elements of the circuit. It is measured in volt-amperes reactive (VAR).

To find the reactive power, we need to know the average power (P) and the power factor (PF) of the circuit.

1. Average Power (P): The average power is given as 5W in the question.

2. Power Factor (PF): The power factor is the cosine of the phase angle between the voltage and current waveforms in an AC circuit. It is a measure of how effectively the circuit converts electrical power into useful work. It ranges from 0 to 1, where 1 represents a purely resistive load and 0 represents a purely reactive load.

Since the question does not provide the power factor, we need to use the relationship between average power, reactive power, and apparent power to find the reactive power.

The relationship is given by the formula:

P = √(S^2 - Q^2)

where P is the average power, S is the apparent power, and Q is the reactive power.

3. Apparent Power (S): The apparent power is the combination of real power (P) and reactive power (Q). It is measured in volt-amperes (VA).

Using the formula above, we can rearrange it to solve for Q:

Q = √(S^2 - P^2)

Since the question provides the average power as 5W, we can substitute it into the formula:

Q = √(S^2 - 5^2)

Now, we need to find the apparent power (S) to calculate the reactive power.

Since the question does not provide the apparent power, we cannot determine the exact value of the reactive power. However, we can determine that the reactive power is greater than 5 VAR because the average power is 5W and reactive power is always greater than or equal to the average power.

Therefore, the correct answer is option 'A' - 10 VAR. This is the only option that is greater than 5 VAR.