Mechanical Engineering Exam > Mechanical Engineering Questions > A fuel is a mixture of 60% methane and 30% ca...
Start Learning for Free
A fuel is a mixture of 60% methane and 30% carbon mono-oxide and 10% oxygen by volume. Calculate the stoichiometric oxygen needed.
- a)1.35 m3
- b)1.25 m3
- c)1 m3
- d)2 m3
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
A fuel is a mixture of 60% methane and 30% carbon mono-oxide and 10% o...
CH4 + 202 → CO2 + 2 H2O
∴ 1 m3 of methane requires 2 m3 of oxygen
∴ 0.6 m3 of methane requires 1.2 m3 of oxygen
2 CO + O2 → 2 CO2
1 m3 of CO requires 0.5 m3 of oxygen, so 0.3 m3 of CO requires 0.15 m3 of oxygen
∴ Total oxygen requires = 1.2 + 0.15 = 1.35 m3
Oxygen already present = 0.1 m3
∴ Stoichiometric oxygen needed = 1.25 m3
Most Upvoted Answer
A fuel is a mixture of 60% methane and 30% carbon mono-oxide and 10% o...
Understanding the Fuel Composition
The fuel consists of:
- 60% Methane (CH₄)
- 30% Carbon Monoxide (CO)
- 10% Oxygen (O₂)
To calculate the stoichiometric oxygen needed, we need to understand the combustion reactions of methane and carbon monoxide.
Combustion Reactions
1. **Methane (CH₄)**:
The balanced reaction is:
\[
CH₄ + 2O₂ \rightarrow CO₂ + 2H₂O
\]
This equation indicates that 1 volume of methane requires 2 volumes of oxygen.
2. **Carbon Monoxide (CO)**:
The balanced reaction is:
\[
2CO + O₂ \rightarrow 2CO₂
\]
This equation shows that 2 volumes of carbon monoxide require 1 volume of oxygen.
Calculating Stoichiometric Oxygen
Now, let’s calculate the total oxygen needed for the given fuel mixture:
- **Methane Portion**:
- Volume of methane = 60% of 1 m³ = 0.6 m³
- Oxygen needed = \(0.6 \times 2 = 1.2 \, m³\)
- **Carbon Monoxide Portion**:
- Volume of carbon monoxide = 30% of 1 m³ = 0.3 m³
- Oxygen needed = \(\frac{0.3}{2} = 0.15 \, m³\)
Total Stoichiometric Oxygen Required
Now, sum up the oxygen needed from both components:
\[
\text{Total O₂} = 1.2 \, m³ + 0.15 \, m³ = 1.35 \, m³
\]
However, we must consider that the fuel already contains 10% (0.1 m³) of oxygen.
Final Calculation
Subtract the available oxygen from the total required:
\[
\text{Required O₂} = 1.35 \, m³ - 0.1 \, m³ = 1.25 \, m³
\]
Thus, the stoichiometric oxygen needed is **1.25 m³**, which corresponds to option 'B'.
The fuel consists of:
- 60% Methane (CH₄)
- 30% Carbon Monoxide (CO)
- 10% Oxygen (O₂)
To calculate the stoichiometric oxygen needed, we need to understand the combustion reactions of methane and carbon monoxide.
Combustion Reactions
1. **Methane (CH₄)**:
The balanced reaction is:
\[
CH₄ + 2O₂ \rightarrow CO₂ + 2H₂O
\]
This equation indicates that 1 volume of methane requires 2 volumes of oxygen.
2. **Carbon Monoxide (CO)**:
The balanced reaction is:
\[
2CO + O₂ \rightarrow 2CO₂
\]
This equation shows that 2 volumes of carbon monoxide require 1 volume of oxygen.
Calculating Stoichiometric Oxygen
Now, let’s calculate the total oxygen needed for the given fuel mixture:
- **Methane Portion**:
- Volume of methane = 60% of 1 m³ = 0.6 m³
- Oxygen needed = \(0.6 \times 2 = 1.2 \, m³\)
- **Carbon Monoxide Portion**:
- Volume of carbon monoxide = 30% of 1 m³ = 0.3 m³
- Oxygen needed = \(\frac{0.3}{2} = 0.15 \, m³\)
Total Stoichiometric Oxygen Required
Now, sum up the oxygen needed from both components:
\[
\text{Total O₂} = 1.2 \, m³ + 0.15 \, m³ = 1.35 \, m³
\]
However, we must consider that the fuel already contains 10% (0.1 m³) of oxygen.
Final Calculation
Subtract the available oxygen from the total required:
\[
\text{Required O₂} = 1.35 \, m³ - 0.1 \, m³ = 1.25 \, m³
\]
Thus, the stoichiometric oxygen needed is **1.25 m³**, which corresponds to option 'B'.
|
Explore Courses for Mechanical Engineering exam
|
|
Top Courses for Mechanical EngineeringView all
Question Description
A fuel is a mixture of 60% methane and 30% carbon mono-oxide and 10% oxygen by volume. Calculate the stoichiometric oxygen needed.a)1.35 m3b)1.25 m3c)1 m3d)2 m3Correct answer is option 'B'. Can you explain this answer? for Mechanical Engineering 2025 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about A fuel is a mixture of 60% methane and 30% carbon mono-oxide and 10% oxygen by volume. Calculate the stoichiometric oxygen needed.a)1.35 m3b)1.25 m3c)1 m3d)2 m3Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A fuel is a mixture of 60% methane and 30% carbon mono-oxide and 10% oxygen by volume. Calculate the stoichiometric oxygen needed.a)1.35 m3b)1.25 m3c)1 m3d)2 m3Correct answer is option 'B'. Can you explain this answer?.
A fuel is a mixture of 60% methane and 30% carbon mono-oxide and 10% oxygen by volume. Calculate the stoichiometric oxygen needed.a)1.35 m3b)1.25 m3c)1 m3d)2 m3Correct answer is option 'B'. Can you explain this answer? for Mechanical Engineering 2025 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about A fuel is a mixture of 60% methane and 30% carbon mono-oxide and 10% oxygen by volume. Calculate the stoichiometric oxygen needed.a)1.35 m3b)1.25 m3c)1 m3d)2 m3Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A fuel is a mixture of 60% methane and 30% carbon mono-oxide and 10% oxygen by volume. Calculate the stoichiometric oxygen needed.a)1.35 m3b)1.25 m3c)1 m3d)2 m3Correct answer is option 'B'. Can you explain this answer?.
Solutions for A fuel is a mixture of 60% methane and 30% carbon mono-oxide and 10% oxygen by volume. Calculate the stoichiometric oxygen needed.a)1.35 m3b)1.25 m3c)1 m3d)2 m3Correct answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for Mechanical Engineering.
Download more important topics, notes, lectures and mock test series for Mechanical Engineering Exam by signing up for free.
Here you can find the meaning of A fuel is a mixture of 60% methane and 30% carbon mono-oxide and 10% oxygen by volume. Calculate the stoichiometric oxygen needed.a)1.35 m3b)1.25 m3c)1 m3d)2 m3Correct answer is option 'B'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
A fuel is a mixture of 60% methane and 30% carbon mono-oxide and 10% oxygen by volume. Calculate the stoichiometric oxygen needed.a)1.35 m3b)1.25 m3c)1 m3d)2 m3Correct answer is option 'B'. Can you explain this answer?, a detailed solution for A fuel is a mixture of 60% methane and 30% carbon mono-oxide and 10% oxygen by volume. Calculate the stoichiometric oxygen needed.a)1.35 m3b)1.25 m3c)1 m3d)2 m3Correct answer is option 'B'. Can you explain this answer? has been provided alongside types of A fuel is a mixture of 60% methane and 30% carbon mono-oxide and 10% oxygen by volume. Calculate the stoichiometric oxygen needed.a)1.35 m3b)1.25 m3c)1 m3d)2 m3Correct answer is option 'B'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice A fuel is a mixture of 60% methane and 30% carbon mono-oxide and 10% oxygen by volume. Calculate the stoichiometric oxygen needed.a)1.35 m3b)1.25 m3c)1 m3d)2 m3Correct answer is option 'B'. Can you explain this answer? tests, examples and also practice Mechanical Engineering tests.
|
|
Explore Courses for Mechanical Engineering exam
|
|
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup