What is the no. of trials of a binomial distribution having mean and S...
Meaning of Binomial Distribution
Before we move ahead to solve the problem, let's first understand the concept of binomial distribution.
A binomial distribution is a probability distribution that describes the number of successes in a fixed number of independent trials, where the probability of success remains the same in all the trials. The distribution can be represented by two parameters - n and p, where n is the number of trials and p is the probability of success in each trial.
The mean of a binomial distribution is given by the formula:
μ = n × p
The standard deviation of a binomial distribution is given by the formula:
σ = √(n × p × (1 - p))
Solving the Problem
Now, let's solve the given problem step by step.
Given,
Mean (μ) = 3
Standard deviation (σ) = 1.5
We know that,
μ = n × p
σ = √(n × p × (1 - p))
Let's substitute the given values in these formulas and solve for n and p.
From the first equation, we get:
p = μ / n
Substituting the value of μ and p, we get:
3 = n × (μ / n)
3 = μ
So, n = 3 / μ = 3 / 3 = 1
Now, let's substitute the values of n and μ in the second equation:
σ = √(n × p × (1 - p))
1.5 = √(1 × p × (1 - p))
Squaring both sides, we get:
2.25 = p × (1 - p)
2.25 = p - p^2
Rearranging, we get:
p^2 - p + 2.25 = 0
Solving this quadratic equation, we get:
p = 1.5, 0.5
Since the probability of success cannot be greater than 1, we reject the value p = 1.5.
Therefore, p = 0.5
Now, we know that n = 1 and p = 0.5.
The number of trials in a binomial distribution is given by n. Therefore, the answer is:
No. of trials (n) = 3 / μ = 3 / 3 = 1 / p = 1 / 0.5 = 2
But, the question asks for the number of trials in a binomial distribution having mean and SD as 3 and 1.5 respectively. Since we have found the values of n and p, we can check if they satisfy the given conditions.
Mean (μ) = n × p = 1 × 0.5 = 0.5 ≠ 3
Standard deviation (σ) = √(n × p × (1 - p)) = √(1 × 0.5 × 0.5) = 0.5 ≠ 1.5
Therefore, the values of n and p that we have found do not satisfy the given conditions.
We need to go back and check our calculations.
From the equation p^2 - p + 2.25 = 0, we get two values of p:
p = 1.5, -0.5
We reject the negative value of p.
Therefore, p =
What is the no. of trials of a binomial distribution having mean and S...
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