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What is the no. of trials of a binomial distribution having mean and SD as 3 and 1.5 respectively?
  • a)
    2.
  • b)
    4.
  • c)
    8.
  • d)
    12.
Correct answer is option 'D'. Can you explain this answer?
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What is the no. of trials of a binomial distribution having mean and S...
Meaning of Binomial Distribution

Before we move ahead to solve the problem, let's first understand the concept of binomial distribution.

A binomial distribution is a probability distribution that describes the number of successes in a fixed number of independent trials, where the probability of success remains the same in all the trials. The distribution can be represented by two parameters - n and p, where n is the number of trials and p is the probability of success in each trial.

The mean of a binomial distribution is given by the formula:

μ = n × p

The standard deviation of a binomial distribution is given by the formula:

σ = √(n × p × (1 - p))

Solving the Problem

Now, let's solve the given problem step by step.

Given,

Mean (μ) = 3

Standard deviation (σ) = 1.5

We know that,

μ = n × p

σ = √(n × p × (1 - p))

Let's substitute the given values in these formulas and solve for n and p.

From the first equation, we get:

p = μ / n

Substituting the value of μ and p, we get:

3 = n × (μ / n)

3 = μ

So, n = 3 / μ = 3 / 3 = 1

Now, let's substitute the values of n and μ in the second equation:

σ = √(n × p × (1 - p))

1.5 = √(1 × p × (1 - p))

Squaring both sides, we get:

2.25 = p × (1 - p)

2.25 = p - p^2

Rearranging, we get:

p^2 - p + 2.25 = 0

Solving this quadratic equation, we get:

p = 1.5, 0.5

Since the probability of success cannot be greater than 1, we reject the value p = 1.5.

Therefore, p = 0.5

Now, we know that n = 1 and p = 0.5.

The number of trials in a binomial distribution is given by n. Therefore, the answer is:

No. of trials (n) = 3 / μ = 3 / 3 = 1 / p = 1 / 0.5 = 2

But, the question asks for the number of trials in a binomial distribution having mean and SD as 3 and 1.5 respectively. Since we have found the values of n and p, we can check if they satisfy the given conditions.

Mean (μ) = n × p = 1 × 0.5 = 0.5 ≠ 3

Standard deviation (σ) = √(n × p × (1 - p)) = √(1 × 0.5 × 0.5) = 0.5 ≠ 1.5

Therefore, the values of n and p that we have found do not satisfy the given conditions.

We need to go back and check our calculations.

From the equation p^2 - p + 2.25 = 0, we get two values of p:

p = 1.5, -0.5

We reject the negative value of p.

Therefore, p =
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What is the no. of trials of a binomial distribution having mean and SD as 3 and 1.5 respectively?a)2.b)4.c)8.d)12.Correct answer is option 'D'. Can you explain this answer?
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What is the no. of trials of a binomial distribution having mean and SD as 3 and 1.5 respectively?a)2.b)4.c)8.d)12.Correct answer is option 'D'. Can you explain this answer? for CA Foundation 2024 is part of CA Foundation preparation. The Question and answers have been prepared according to the CA Foundation exam syllabus. Information about What is the no. of trials of a binomial distribution having mean and SD as 3 and 1.5 respectively?a)2.b)4.c)8.d)12.Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for CA Foundation 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for What is the no. of trials of a binomial distribution having mean and SD as 3 and 1.5 respectively?a)2.b)4.c)8.d)12.Correct answer is option 'D'. Can you explain this answer?.
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