The HCF of two numbers is 16 and their product is 3072. What is the LC...
Given information:
- HCF of two numbers = 16
- Product of two numbers = 3072
Finding the two numbers:
Let the two numbers be a and b.
Given that HCF(a, b) = 16, we can write the two numbers as:
a = 16x
b = 16y
where x and y are co-prime numbers.
The product of the two numbers is given as 3072:
16x * 16y = 3072
256xy = 3072
xy = 12
So, the possible values of x and y could be:
x = 1, y = 12
x = 2, y = 6
x = 3, y = 4
Therefore, the two numbers could be:
a = 16 * 1 = 16, b = 16 * 12 = 192
a = 16 * 2 = 32, b = 16 * 6 = 96
a = 16 * 3 = 48, b = 16 * 4 = 64
Calculating the LCM:
To find the LCM of two numbers, we can use the formula:
LCM(a, b) = (a * b) / HCF(a, b)
Substitute the values of a, b, and HCF in the formula:
LCM(16, 192) = (16 * 192) / 16
LCM(16, 192) = 3072 / 16
LCM(16, 192) = 192
Therefore, the LCM of the two numbers is 192, which corresponds to option 'c'.
The HCF of two numbers is 16 and their product is 3072. What is the LC...
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