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A water jet of 5 cm diameter moves with a constant velocity of 20 m/s and strikes a stationary and symmetrical curved plate at the centre. If the jet is deflected through an angle of 120° at the inlet and of the current plate, the force exceeded by the water jet in the direction of jet will be
  • a)
    2.54 kN
  • b)
    1.78 kN
  • c)
    6.32 kN
  • d)
    3.49 kN
Correct answer is option 'B'. Can you explain this answer?
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A water jet of 5 cm diameter moves with a constant velocity of 20 m/s ...


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A water jet of 5 cm diameter moves with a constant velocity of 20 m/s ...
Given:
Diameter of water jet (d) = 5 cm
Velocity of water jet (V) = 20 m/s
Deflection angle (θ) = 120°

To find:
Force exceeded by the water jet in the direction of the jet

Solution:
1. Area of water jet (A) = πd²/4
A = π(0.05)²/4
A = 0.00196 m²

2. Mass flow rate of water (m) = ρAV
Where ρ is the density of water.
Let's assume the density of water as 1000 kg/m³
m = 1000 × 0.00196 × 20
m = 39.2 kg/s

3. Change in momentum of water (Δp) = 2mV sin(θ/2)
Δp = 2 × 39.2 × 20 sin(120/2)
Δp = 3920 Ns

4. Force exerted by water jet (F) = Δp/t
Where t is the time taken by water to change its momentum.
t = d/V
t = 0.05/20
t = 0.0025 s
F = Δp/t
F = 3920/0.0025
F = 1,568,000 N

5. Force exceeded by water jet in the direction of jet (Fex) = F sin(θ/2)
Fex = 1568000 sin(120/2)
Fex = 1778.8 N
Fex ≈ 1.78 kN

Therefore, the force exceeded by the water jet in the direction of the jet is 1.78 kN (approx).
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A water jet of 5 cm diameter moves with a constant velocity of 20 m/s and strikes a stationary and symmetrical curved plate at the centre. If the jet is deflected through an angle of 120° at the inlet and of the current plate, the force exceeded by the water jet in the direction of jet will bea)2.54 kNb)1.78 kNc)6.32 kNd)3.49 kNCorrect answer is option 'B'. Can you explain this answer?
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A water jet of 5 cm diameter moves with a constant velocity of 20 m/s and strikes a stationary and symmetrical curved plate at the centre. If the jet is deflected through an angle of 120° at the inlet and of the current plate, the force exceeded by the water jet in the direction of jet will bea)2.54 kNb)1.78 kNc)6.32 kNd)3.49 kNCorrect answer is option 'B'. Can you explain this answer? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about A water jet of 5 cm diameter moves with a constant velocity of 20 m/s and strikes a stationary and symmetrical curved plate at the centre. If the jet is deflected through an angle of 120° at the inlet and of the current plate, the force exceeded by the water jet in the direction of jet will bea)2.54 kNb)1.78 kNc)6.32 kNd)3.49 kNCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A water jet of 5 cm diameter moves with a constant velocity of 20 m/s and strikes a stationary and symmetrical curved plate at the centre. If the jet is deflected through an angle of 120° at the inlet and of the current plate, the force exceeded by the water jet in the direction of jet will bea)2.54 kNb)1.78 kNc)6.32 kNd)3.49 kNCorrect answer is option 'B'. Can you explain this answer?.
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