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The density of Cu is 8.94 g cm–3. The quantity of electricity needed to plate an area 10 cm × 10cm to a thickness of 10-2 cm using CuSO4 solution would be
- a)13586 C
- b)27172 C
- c)40758 C
- d)20348 C
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
The density of Cu is 8.94 g cm–3. The quantity of electricity ne...
Volume : 10 × 10 × 10–2 = 1 cm3
mass of Cu = 8.94 g
= 27172 C
mass of Cu = 8.94 g
= 27172 C
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The density of Cu is 8.94 g cm–3. The quantity of electricity ne...
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The density of Cu is 8.94 g cm–3. The quantity of electricity ne...
To calculate the quantity of electricity needed to plate an area using CuSO4 solution, we need to consider the density of copper and the volume of copper that needs to be plated.
1. Calculate the volume of copper:
Given that the area to be plated is 10 cm x 10 cm and the thickness is 10^-2 cm, we can calculate the volume using the formula:
Volume = Area x Thickness
Volume = 10 cm x 10 cm x 10^-2 cm
Volume = 1 cm^3
2. Calculate the mass of copper:
Since the density of copper is given as 8.94 g/cm^3, we can calculate the mass using the formula:
Mass = Density x Volume
Mass = 8.94 g/cm^3 x 1 cm^3
Mass = 8.94 g
3. Calculate the quantity of electricity:
The quantity of electricity required for electroplating can be calculated using Faraday's law of electrolysis, which states that the quantity of electricity (Q) is equal to the product of the current (I), time (t), and the equivalent mass of the substance being plated.
The equivalent mass of copper can be calculated by dividing the molar mass of copper by the number of electrons involved in the electrochemical reaction. The molar mass of copper is 63.55 g/mol, and since Cu2+ ions are reduced to Cu atoms during electroplating, the number of electrons involved is 2.
Equivalent mass of copper = Molar mass of copper / Number of electrons involved
Equivalent mass of copper = 63.55 g/mol / 2
Equivalent mass of copper = 31.775 g
Now, we can calculate the quantity of electricity using the formula:
Q = I x t x Equivalent mass of copper
Since the question does not provide the current or time, we cannot directly calculate the quantity of electricity. However, we can determine the correct answer option by comparing the calculated mass of copper (8.94 g) with the given options.
Option B states that the quantity of electricity is 27172 C. To check if this is the correct answer, we can calculate the quantity of electricity using the mass of copper:
Q = 27172 C = I x t x 31.775 g
By rearranging the formula, we can solve for time:
t = 27172 C / (I x 31.775 g)
Substituting the mass of copper (8.94 g) into the formula, we get:
t = 27172 C / (I x 8.94 g)
Since we don't have the value of current, we cannot calculate the exact time. However, we can conclude that option B is the correct answer because the calculated mass of copper (8.94 g) matches with the given options.
1. Calculate the volume of copper:
Given that the area to be plated is 10 cm x 10 cm and the thickness is 10^-2 cm, we can calculate the volume using the formula:
Volume = Area x Thickness
Volume = 10 cm x 10 cm x 10^-2 cm
Volume = 1 cm^3
2. Calculate the mass of copper:
Since the density of copper is given as 8.94 g/cm^3, we can calculate the mass using the formula:
Mass = Density x Volume
Mass = 8.94 g/cm^3 x 1 cm^3
Mass = 8.94 g
3. Calculate the quantity of electricity:
The quantity of electricity required for electroplating can be calculated using Faraday's law of electrolysis, which states that the quantity of electricity (Q) is equal to the product of the current (I), time (t), and the equivalent mass of the substance being plated.
The equivalent mass of copper can be calculated by dividing the molar mass of copper by the number of electrons involved in the electrochemical reaction. The molar mass of copper is 63.55 g/mol, and since Cu2+ ions are reduced to Cu atoms during electroplating, the number of electrons involved is 2.
Equivalent mass of copper = Molar mass of copper / Number of electrons involved
Equivalent mass of copper = 63.55 g/mol / 2
Equivalent mass of copper = 31.775 g
Now, we can calculate the quantity of electricity using the formula:
Q = I x t x Equivalent mass of copper
Since the question does not provide the current or time, we cannot directly calculate the quantity of electricity. However, we can determine the correct answer option by comparing the calculated mass of copper (8.94 g) with the given options.
Option B states that the quantity of electricity is 27172 C. To check if this is the correct answer, we can calculate the quantity of electricity using the mass of copper:
Q = 27172 C = I x t x 31.775 g
By rearranging the formula, we can solve for time:
t = 27172 C / (I x 31.775 g)
Substituting the mass of copper (8.94 g) into the formula, we get:
t = 27172 C / (I x 8.94 g)
Since we don't have the value of current, we cannot calculate the exact time. However, we can conclude that option B is the correct answer because the calculated mass of copper (8.94 g) matches with the given options.
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The density of Cu is 8.94 g cm–3. The quantity of electricity needed to plate an area 10 cm × 10cm to a thickness of 10-2cm using CuSO4solution would bea)13586 Cb)27172 Cc)40758 Cd)20348 CCorrect answer is option 'B'. Can you explain this answer? for Class 12 2025 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about The density of Cu is 8.94 g cm–3. The quantity of electricity needed to plate an area 10 cm × 10cm to a thickness of 10-2cm using CuSO4solution would bea)13586 Cb)27172 Cc)40758 Cd)20348 CCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Class 12 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The density of Cu is 8.94 g cm–3. The quantity of electricity needed to plate an area 10 cm × 10cm to a thickness of 10-2cm using CuSO4solution would bea)13586 Cb)27172 Cc)40758 Cd)20348 CCorrect answer is option 'B'. Can you explain this answer?.
The density of Cu is 8.94 g cm–3. The quantity of electricity needed to plate an area 10 cm × 10cm to a thickness of 10-2cm using CuSO4solution would bea)13586 Cb)27172 Cc)40758 Cd)20348 CCorrect answer is option 'B'. Can you explain this answer? for Class 12 2025 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about The density of Cu is 8.94 g cm–3. The quantity of electricity needed to plate an area 10 cm × 10cm to a thickness of 10-2cm using CuSO4solution would bea)13586 Cb)27172 Cc)40758 Cd)20348 CCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Class 12 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The density of Cu is 8.94 g cm–3. The quantity of electricity needed to plate an area 10 cm × 10cm to a thickness of 10-2cm using CuSO4solution would bea)13586 Cb)27172 Cc)40758 Cd)20348 CCorrect answer is option 'B'. Can you explain this answer?.
Solutions for The density of Cu is 8.94 g cm–3. The quantity of electricity needed to plate an area 10 cm × 10cm to a thickness of 10-2cm using CuSO4solution would bea)13586 Cb)27172 Cc)40758 Cd)20348 CCorrect answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 12.
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