JEE Exam  >  JEE Questions  >  The molar solubility (in mol L–1) of a ... Start Learning for Free
The molar solubility (in mol L–1) of a sparingly soluble salt MX4 is ‘s’. The corresponding solubility product is Ksp. ‘s’ is given in term of Ksp by the relation :
  • a)
    s = (256 Ksp)1/5  
  • b)
    s = (128 Ksp)1/4
  • c)
    s = (Ksp / 128)1/4 
  • d)
    s = (Ksp / 256)1/5
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
The molar solubility (in mol L–1) of a sparingly soluble salt MX...

View all questions of this test
Most Upvoted Answer
The molar solubility (in mol L–1) of a sparingly soluble salt MX...
Free Test
Community Answer
The molar solubility (in mol L–1) of a sparingly soluble salt MX...

Explore Courses for JEE exam
The molar solubility (in mol L–1) of a sparingly soluble salt MX4 is ‘s’. The corresponding solubility product is Ksp. ‘s’ is given in term of Ksp by the relation :a)s = (256 Ksp)1/5 b)s = (128 Ksp)1/4c)s = (Ksp / 128)1/4d)s = (Ksp / 256)1/5Correct answer is option 'D'. Can you explain this answer?
Question Description
The molar solubility (in mol L–1) of a sparingly soluble salt MX4 is ‘s’. The corresponding solubility product is Ksp. ‘s’ is given in term of Ksp by the relation :a)s = (256 Ksp)1/5 b)s = (128 Ksp)1/4c)s = (Ksp / 128)1/4d)s = (Ksp / 256)1/5Correct answer is option 'D'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about The molar solubility (in mol L–1) of a sparingly soluble salt MX4 is ‘s’. The corresponding solubility product is Ksp. ‘s’ is given in term of Ksp by the relation :a)s = (256 Ksp)1/5 b)s = (128 Ksp)1/4c)s = (Ksp / 128)1/4d)s = (Ksp / 256)1/5Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The molar solubility (in mol L–1) of a sparingly soluble salt MX4 is ‘s’. The corresponding solubility product is Ksp. ‘s’ is given in term of Ksp by the relation :a)s = (256 Ksp)1/5 b)s = (128 Ksp)1/4c)s = (Ksp / 128)1/4d)s = (Ksp / 256)1/5Correct answer is option 'D'. Can you explain this answer?.
Solutions for The molar solubility (in mol L–1) of a sparingly soluble salt MX4 is ‘s’. The corresponding solubility product is Ksp. ‘s’ is given in term of Ksp by the relation :a)s = (256 Ksp)1/5 b)s = (128 Ksp)1/4c)s = (Ksp / 128)1/4d)s = (Ksp / 256)1/5Correct answer is option 'D'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.
Here you can find the meaning of The molar solubility (in mol L–1) of a sparingly soluble salt MX4 is ‘s’. The corresponding solubility product is Ksp. ‘s’ is given in term of Ksp by the relation :a)s = (256 Ksp)1/5 b)s = (128 Ksp)1/4c)s = (Ksp / 128)1/4d)s = (Ksp / 256)1/5Correct answer is option 'D'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of The molar solubility (in mol L–1) of a sparingly soluble salt MX4 is ‘s’. The corresponding solubility product is Ksp. ‘s’ is given in term of Ksp by the relation :a)s = (256 Ksp)1/5 b)s = (128 Ksp)1/4c)s = (Ksp / 128)1/4d)s = (Ksp / 256)1/5Correct answer is option 'D'. Can you explain this answer?, a detailed solution for The molar solubility (in mol L–1) of a sparingly soluble salt MX4 is ‘s’. The corresponding solubility product is Ksp. ‘s’ is given in term of Ksp by the relation :a)s = (256 Ksp)1/5 b)s = (128 Ksp)1/4c)s = (Ksp / 128)1/4d)s = (Ksp / 256)1/5Correct answer is option 'D'. Can you explain this answer? has been provided alongside types of The molar solubility (in mol L–1) of a sparingly soluble salt MX4 is ‘s’. The corresponding solubility product is Ksp. ‘s’ is given in term of Ksp by the relation :a)s = (256 Ksp)1/5 b)s = (128 Ksp)1/4c)s = (Ksp / 128)1/4d)s = (Ksp / 256)1/5Correct answer is option 'D'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice The molar solubility (in mol L–1) of a sparingly soluble salt MX4 is ‘s’. The corresponding solubility product is Ksp. ‘s’ is given in term of Ksp by the relation :a)s = (256 Ksp)1/5 b)s = (128 Ksp)1/4c)s = (Ksp / 128)1/4d)s = (Ksp / 256)1/5Correct answer is option 'D'. Can you explain this answer? tests, examples and also practice JEE tests.
Explore Courses for JEE exam

Top Courses for JEE

Explore Courses
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
10M+ students study on EduRev