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For a sparingly soluble salt ApBq, the relationship of its solubility product (LS) with its solubility (S) is
- a)LS = S p+q.pp.qq
- b)LS = S p+q.pq.qp
- c)LS = S pq.pp.qq
- d)LS = Spq.(pq)p+q
Correct answer is option 'A'. Can you explain this answer?
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For a sparingly soluble salt ApBq, the relationship of its solubility ...
The correct option: (a) Ls = S^P + q . p^p.q^q
Explanation:
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For a sparingly soluble salt ApBq, the relationship of its solubility ...
Explanation:
Sparingly soluble salts are those salts that have low solubility in water. When a sparingly soluble salt dissolves in water, it dissociates into its constituent ions. The solubility product (LS) is a measure of the extent of dissociation of a sparingly soluble salt in water. It is the product of the concentrations of the ions raised to the power of their stoichiometric coefficients in the balanced chemical equation for the dissolution of the salt.
The solubility (S) of a sparingly soluble salt is defined as the maximum amount of the salt that can dissolve in a given amount of solvent at a particular temperature. It is usually expressed in moles per liter (M).
The relationship between the solubility product (LS) and the solubility (S) of a sparingly soluble salt ApBq is given by the equation LS = S^p * (S^q)^q.
Derivation of the equation:
The dissolution of the sparingly soluble salt ApBq can be represented by the following balanced chemical equation:
ApBq (s) ⇌ aA^q+ (aq) + bB^p- (aq)
The equilibrium expression for the dissolution of the salt can be written as:
LS = [A^q+]^a * [B^p-]^b
Since the concentration of a dissolved species is directly proportional to its solubility, we can substitute [A^q+] with S and [B^p-] with S, as both are equal to the solubility of the salt.
Therefore, the equation becomes:
LS = S^a * S^b
Simplifying further:
LS = S^(a+b) = S^(p+q)
Hence, the relationship between the solubility product (LS) and the solubility (S) of a sparingly soluble salt ApBq is LS = S^p * (S^q)^q, which is represented by option A.
Sparingly soluble salts are those salts that have low solubility in water. When a sparingly soluble salt dissolves in water, it dissociates into its constituent ions. The solubility product (LS) is a measure of the extent of dissociation of a sparingly soluble salt in water. It is the product of the concentrations of the ions raised to the power of their stoichiometric coefficients in the balanced chemical equation for the dissolution of the salt.
The solubility (S) of a sparingly soluble salt is defined as the maximum amount of the salt that can dissolve in a given amount of solvent at a particular temperature. It is usually expressed in moles per liter (M).
The relationship between the solubility product (LS) and the solubility (S) of a sparingly soluble salt ApBq is given by the equation LS = S^p * (S^q)^q.
Derivation of the equation:
The dissolution of the sparingly soluble salt ApBq can be represented by the following balanced chemical equation:
ApBq (s) ⇌ aA^q+ (aq) + bB^p- (aq)
The equilibrium expression for the dissolution of the salt can be written as:
LS = [A^q+]^a * [B^p-]^b
Since the concentration of a dissolved species is directly proportional to its solubility, we can substitute [A^q+] with S and [B^p-] with S, as both are equal to the solubility of the salt.
Therefore, the equation becomes:
LS = S^a * S^b
Simplifying further:
LS = S^(a+b) = S^(p+q)
Hence, the relationship between the solubility product (LS) and the solubility (S) of a sparingly soluble salt ApBq is LS = S^p * (S^q)^q, which is represented by option A.
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For a sparingly soluble salt ApBq, the relationship of its solubility product (LS) with its solubility (S) isa)LS = S p+q.pp.qqb)LS = S p+q.pq.qpc)LS = S pq.pp.qqd)LS = Spq.(pq)p+qCorrect answer is option 'A'. Can you explain this answer?
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