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For a sparingly soluble salt ApBq, the relationship of its solubility product Ls → Ksp with its solubility (S) is
- a)Ls → Ksp = Spq (pq)P + q
- b)Ls = Sp + q . ppqq
- c)Ls → Ksp = Sp + q . pqqp
- d)Ls → Ksp = Spqppqq
Correct answer is option 'B'. Can you explain this answer?
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For a sparingly soluble salt ApBq, the relationship of its solubility ...
Let the solubility be S mol/liter Thus,
Ksp = [A +]p [B–]q
= [Sp]p [Sq]q = p p.qq (S)p+q .
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For a sparingly soluble salt ApBq, the relationship of its solubility ...
And its molar solubility Sm is given by the following equation:
Ls = (Sm)^(p+q)
where p and q are the stoichiometric coefficients of A and B in the chemical formula of the salt. This relationship is known as the solubility product expression or equilibrium constant expression.
For example, if the chemical formula of the salt is AB2, then p=1 and q=2, and the solubility product expression would be:
Ls = (Sm)^3
This means that the solubility product increases rapidly with increasing molar solubility, and a small increase in the molar solubility can result in a large increase in the solubility product. Therefore, the solubility product is a measure of the extent to which the salt dissolves in a given solvent, and it can be used to predict the concentration of ions in a saturated solution or to calculate the solubility of the salt under different conditions.
Ls = (Sm)^(p+q)
where p and q are the stoichiometric coefficients of A and B in the chemical formula of the salt. This relationship is known as the solubility product expression or equilibrium constant expression.
For example, if the chemical formula of the salt is AB2, then p=1 and q=2, and the solubility product expression would be:
Ls = (Sm)^3
This means that the solubility product increases rapidly with increasing molar solubility, and a small increase in the molar solubility can result in a large increase in the solubility product. Therefore, the solubility product is a measure of the extent to which the salt dissolves in a given solvent, and it can be used to predict the concentration of ions in a saturated solution or to calculate the solubility of the salt under different conditions.
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For a sparingly soluble salt ApBq, the relationship of its solubility product Ls → Ksp with its solubility (S) isa)Ls → Ksp = Spq (pq)P + qb)Ls = Sp + q . ppqqc)Ls → Ksp = Sp + q . pqqpd)Ls → Ksp = SpqppqqCorrect answer is option 'B'. Can you explain this answer?
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For a sparingly soluble salt ApBq, the relationship of its solubility product Ls → Ksp with its solubility (S) isa)Ls → Ksp = Spq (pq)P + qb)Ls = Sp + q . ppqqc)Ls → Ksp = Sp + q . pqqpd)Ls → Ksp = SpqppqqCorrect answer is option 'B'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about For a sparingly soluble salt ApBq, the relationship of its solubility product Ls → Ksp with its solubility (S) isa)Ls → Ksp = Spq (pq)P + qb)Ls = Sp + q . ppqqc)Ls → Ksp = Sp + q . pqqpd)Ls → Ksp = SpqppqqCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for For a sparingly soluble salt ApBq, the relationship of its solubility product Ls → Ksp with its solubility (S) isa)Ls → Ksp = Spq (pq)P + qb)Ls = Sp + q . ppqqc)Ls → Ksp = Sp + q . pqqpd)Ls → Ksp = SpqppqqCorrect answer is option 'B'. Can you explain this answer?.
For a sparingly soluble salt ApBq, the relationship of its solubility product Ls → Ksp with its solubility (S) isa)Ls → Ksp = Spq (pq)P + qb)Ls = Sp + q . ppqqc)Ls → Ksp = Sp + q . pqqpd)Ls → Ksp = SpqppqqCorrect answer is option 'B'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about For a sparingly soluble salt ApBq, the relationship of its solubility product Ls → Ksp with its solubility (S) isa)Ls → Ksp = Spq (pq)P + qb)Ls = Sp + q . ppqqc)Ls → Ksp = Sp + q . pqqpd)Ls → Ksp = SpqppqqCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for For a sparingly soluble salt ApBq, the relationship of its solubility product Ls → Ksp with its solubility (S) isa)Ls → Ksp = Spq (pq)P + qb)Ls = Sp + q . ppqqc)Ls → Ksp = Sp + q . pqqpd)Ls → Ksp = SpqppqqCorrect answer is option 'B'. Can you explain this answer?.
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