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A body from height h is dropped. If the coefficient of restitution is e, then calculate the height achieved after one bounce.
  • a)
    h1 = e2h
  • b)
    h1 = e4h
  • c)
    h1 = e h
  • d)
    h1 = h/e
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
A body from height h is dropped. If the coefficient of restitution is ...
We know that,
u=√2gh.....
Nd coefficient of restitution (e) =v/u
so by putting the value of both the velocities.
we have, e=√2gx/√2gh
so x=e^2h
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Community Answer
A body from height h is dropped. If the coefficient of restitution is ...
When a body falls from a height h, it strikes the ground with a velocity μ = √2gh Let it rebounds with a velocity v and rise to a height h1
If the successive heights to which the body rebounds again and again are h2, h3,...., then
Clearly, h1 = e2 h, h2 = e4 h ... and so on. Similarly, after nth rebound
hn = (e2n)h
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A body from height h is dropped. If the coefficient of restitution is e, then calculate the height achieved after one bounce.a)h1 = e2hb)h1 = e4hc)h1 = e hd)h1 = h/eCorrect answer is option 'A'. Can you explain this answer?
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