Answer:

Motion is the change in position of an object with respect to time. The study of motion is an essential part of physics and is used to describe the behavior of objects in various situations. In this question, we will discuss the motion of a train that starts its journey from station P and accelerates at the rate of 2 m/s.

Initial Velocity

The train is initially at rest, so its initial velocity is zero. This means that the train is not moving at the beginning of its journey.

Acceleration

The train accelerates at the rate of 2 m/s. This means that its velocity increases by 2 m/s every second. The formula for acceleration is a = (v-u)/t, where a is the acceleration, v is the final velocity, u is the initial velocity, and t is the time taken for the change in velocity.

Distance Traveled

The distance traveled by the train can be calculated using the formula s = ut + 1/2 at^2, where s is the distance traveled, u is the initial velocity, a is the acceleration, and t is the time taken.

Final Velocity

The final velocity of the train can be calculated using the formula v = u + at, where v is the final velocity, u is the initial velocity, a is the acceleration, and t is the time taken.

Example Calculation

Suppose the train starts its journey from station P and accelerates at the rate of 2 m/s. After 10 seconds, it reaches a velocity of 20 m/s. What is the distance traveled by the train?

Using the formula s = ut + 1/2 at^2, we get:

s = 0(10) + 1/2 (2) (10)^2
s = 100 meters

Therefore, the train has traveled a distance of 100 meters in 10 seconds.

Conclusion

In conclusion, the motion of an object can be described by its initial velocity, acceleration, distance traveled, and final velocity. The formulae discussed in this question can be used to calculate various parameters of motion. In the case of the train starting its journey from station P and accelerating at the rate of 2 m/s, we can use these formulae to calculate its distance traveled and final velocity.