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A body is moving with uniform acceleration and describes 75 m
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A body is moving with uniform acceleration and describes 75 m Related:...
**Uniform Acceleration and Motion**

When a body experiences uniform acceleration, it means that its velocity is changing at a constant rate. This change in velocity can be either an increase or decrease, depending on the direction of the acceleration. In this case, the body is moving with uniform acceleration and describes a distance of 75 m.

**Equations of Motion**

To analyze the motion of the body, we can use the equations of motion. These equations relate the initial velocity (u), final velocity (v), acceleration (a), displacement (s), and time (t) of the body.

The equations of motion are as follows:

1. v = u + at
2. s = ut + 1/2 at^2
3. v^2 = u^2 + 2as

where:
- v is the final velocity
- u is the initial velocity
- a is the acceleration
- s is the displacement
- t is the time

**Using the Equations of Motion**

To determine the values of the variables in the given problem, we need to know which variables are given and which ones are unknown.

Given:
- s = 75 m
- u (initial velocity) is not provided
- a (acceleration) is not provided

Unknown:
- v (final velocity)
- t (time)

Since the body is moving with uniform acceleration, we can assume that the initial velocity is zero (u = 0). This allows us to simplify the equations of motion.

**Using the First Equation of Motion**

Using the first equation of motion, we can calculate the final velocity (v) when the initial velocity (u) is zero and the acceleration (a) is unknown:

v = u + at
v = 0 + at
v = at

**Using the Second Equation of Motion**

Using the second equation of motion, we can calculate the displacement (s) when the initial velocity (u) is zero and the acceleration (a) is unknown:

s = ut + 1/2 at^2
s = 0t + 1/2 at^2
s = 1/2 at^2

**Using the Third Equation of Motion**

Using the third equation of motion, we can relate the final velocity (v), initial velocity (u), acceleration (a), and displacement (s):

v^2 = u^2 + 2as
v^2 = 0^2 + 2a(1/2 at^2)
v^2 = 0 + a^2t^2
v^2 = a^2t^2

**Solving for v and t**

From the equation v = at, we can see that the final velocity (v) is directly proportional to the acceleration (a) and time (t). This means that if we know the values of a and t, we can determine the value of v.

Similarly, from the equation s = 1/2 at^2, we can see that the displacement (s) is directly proportional to the acceleration (a) and the square of the time (t^2). This means that if we know the values of a and s, we can determine the value of t.

However, since both a and t are unknown in this problem, we cannot directly calculate the values of v and t. We need additional information to solve the problem.

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A body is moving with uniform acceleration and describes 75 m Related:...
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