Question Description
If 18 gram of glucose (C6H12O6) is present in 1000 gram of an aqueous solution of glucose it is said to be-a)39.2 gramb)1.1 molalc)0.5 molald)0.1 molalCorrect answer is option 'D'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about If 18 gram of glucose (C6H12O6) is present in 1000 gram of an aqueous solution of glucose it is said to be-a)39.2 gramb)1.1 molalc)0.5 molald)0.1 molalCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If 18 gram of glucose (C6H12O6) is present in 1000 gram of an aqueous solution of glucose it is said to be-a)39.2 gramb)1.1 molalc)0.5 molald)0.1 molalCorrect answer is option 'D'. Can you explain this answer?.

Solutions for If 18 gram of glucose (C6H12O6) is present in 1000 gram of an aqueous solution of glucose it is said to be-a)39.2 gramb)1.1 molalc)0.5 molald)0.1 molalCorrect answer is option 'D'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 12. Download more important topics, notes, lectures and mock test series for Class 12 Exam by signing up for free.

Here you can find the meaning of If 18 gram of glucose (C6H12O6) is present in 1000 gram of an aqueous solution of glucose it is said to be-a)39.2 gramb)1.1 molalc)0.5 molald)0.1 molalCorrect answer is option 'D'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of If 18 gram of glucose (C6H12O6) is present in 1000 gram of an aqueous solution of glucose it is said to be-a)39.2 gramb)1.1 molalc)0.5 molald)0.1 molalCorrect answer is option 'D'. Can you explain this answer?, a detailed solution for If 18 gram of glucose (C6H12O6) is present in 1000 gram of an aqueous solution of glucose it is said to be-a)39.2 gramb)1.1 molalc)0.5 molald)0.1 molalCorrect answer is option 'D'. Can you explain this answer? has been provided alongside types of If 18 gram of glucose (C6H12O6) is present in 1000 gram of an aqueous solution of glucose it is said to be-a)39.2 gramb)1.1 molalc)0.5 molald)0.1 molalCorrect answer is option 'D'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice If 18 gram of glucose (C6H12O6) is present in 1000 gram of an aqueous solution of glucose it is said to be-a)39.2 gramb)1.1 molalc)0.5 molald)0.1 molalCorrect answer is option 'D'. Can you explain this answer? tests, examples and also practice Class 12 tests.