Which one of the following pairs of solution can we expect to be isoto...
Isotonic means equal osmotic pressure so, π1 = π2
i1C1RT = i2C2RT
so i1C1 = i2C2
In case of (D) both the volume of (i) & (C) are equal.
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Which one of the following pairs of solution can we expect to be isoto...
Isotonic Solutions:
Isotonic solutions are solutions that have the same concentration of solutes and the same osmotic pressure across a semipermeable membrane. When two solutions are isotonic, there is no net movement of water across the membrane.
Explanation:
To determine which pair of solutions can be expected to be isotonic, we need to compare the concentrations of the solutes in each pair. Let's analyze each option:
a) 0.1 M urea and 0.1 M NaCl:
- Urea is a small molecule and NaCl dissociates into Na+ and Cl- ions in water.
- Since urea is a non-ionic solute and NaCl dissociates, the concentration of solute particles in the NaCl solution is higher than in the urea solution.
- Therefore, these solutions have different concentrations of solutes and cannot be isotonic.
b) 0.1 M urea and 0.2 M MgCl2:
- Urea is a non-ionic solute and MgCl2 dissociates into Mg2+ and Cl- ions in water.
- Similar to the previous case, the concentration of solute particles in the MgCl2 solution is higher than in the urea solution.
- These solutions also have different concentrations of solutes and cannot be isotonic.
c) 0.1 M NaCl and 0.1 M Na2SO4:
- Both NaCl and Na2SO4 dissociate into ions in water.
- Since both solutions have the same concentration of solutes (Na+ and Cl- ions), they can be expected to be isotonic.
d) 0.1 M Ca(NO3)2 and 0.1 M Na2SO4:
- Both Ca(NO3)2 and Na2SO4 dissociate into ions in water.
- Similar to the previous case, both solutions have the same concentration of solutes (Ca2+ and NO3- ions), so they can be expected to be isotonic.
Conclusion:
Based on the analysis above, the pair of solutions that can be expected to be isotonic at the same temperature is 0.1 M Ca(NO3)2 and 0.1 M Na2SO4 (option D).