Yograj Singh's First ODI Match and Wicket Details

In Yograj Singh's first ODI match, he took a total of 2 wickets.

Explanation:

Yograj Singh:
Yograj Singh is a former Indian cricketer who played as a right-arm fast-medium bowler. He was born on March 25, 1958, in Chandigarh, India. Yograj Singh is known for his aggressive style of play and his ability to swing the ball.

ODI Debut:
Yograj Singh made his One Day International (ODI) debut for India on October 5, 1980, against Australia. The match took place at the Melbourne Cricket Ground in Melbourne, Australia.

Wickets Taken:
In his debut ODI match, Yograj Singh managed to take a total of 2 wickets. The details of the wickets are as follows:

1. Wicket 1: Yograj Singh's first wicket came in the 22nd over of the Australian innings. He dismissed Australian opener Graeme Wood. Wood was caught by wicketkeeper Syed Kirmani for 26 runs.

2. Wicket 2: Yograj Singh's second wicket came in the 25th over of the match. He dismissed Australian batsman Kim Hughes. Hughes was caught by Sandeep Patil for 16 runs.

Thus, Yograj Singh ended his first ODI match with 2 wickets to his name.

Conclusion:
Yograj Singh took a total of 2 wickets in his debut ODI match against Australia. He dismissed Graeme Wood and Kim Hughes during the match.