Find the time taken for the current in an inductor to change to 2A fro...
The expression for power in an inductive circuit is:
P= LI2/2
Substituting the values from the given question, we get t=4s.
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Find the time taken for the current in an inductor to change to 2A fro...
Power=1/2LI²
5=1/2*10*I² then I =1amp then v = power/I² v =5volt
v =-Ldi/dt
5=-10(0-2)/dt
dt=20/5 =4 sec
Find the time taken for the current in an inductor to change to 2A fro...
Given data:
- Power in the inductor = 5W
- Inductance = 10H
- Final current = 2A
- Initial current = 0A
Formula:
- Power in an inductor, P = I^2 * R, where R is the resistance of the inductor
- Time constant, τ = L / R
- Time taken to reach final current, t = τ * ln(I_final / I_initial)
Calculation:
- From the given data, Power (P) = 5W
- We know that Power (P) = I^2 * R
- Since the resistance of the inductor is not given, we cannot directly calculate the current. However, we can find the time constant using the formula τ = L / R.
- Given, L = 10H
- Let's assume the resistance R = 1Ω (for simplicity)
- Therefore, time constant, τ = 10 / 1 = 10s
- Now, we can calculate the time taken for the current to change from 0A to 2A using the formula t = τ * ln(I_final / I_initial)
- Substituting the values, t = 10 * ln(2 / 0) = 10 * ln(∞) = 10 * ∞ = ∞
Conclusion:
The time taken for the current in an inductor to change to 2A from 0A is theoretically infinite.