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Find the time taken for the current in an inductor to change to 2A from 0A if the power in the inductor is 5W. The value of inductance is 10H.
- a)1s
- b)2s
- c)3s
- d)4s
Correct answer is option 'D'. Can you explain this answer?
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Verified Answer
Find the time taken for the current in an inductor to change to 2A fro...
The expression for power in an inductive circuit is:
P= LI2/2
Substituting the values from the given question, we get t=4s.
P= LI2/2
Substituting the values from the given question, we get t=4s.
Most Upvoted Answer
Find the time taken for the current in an inductor to change to 2A fro...
Power=1/2LI²
5=1/2*10*I² then I =1amp then v = power/I² v =5volt
v =-Ldi/dt
5=-10(0-2)/dt
dt=20/5 =4 sec
5=1/2*10*I² then I =1amp then v = power/I² v =5volt
v =-Ldi/dt
5=-10(0-2)/dt
dt=20/5 =4 sec
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Find the time taken for the current in an inductor to change to 2A fro...
Given data:
- Power in the inductor = 5W
- Inductance = 10H
- Final current = 2A
- Initial current = 0A
Formula:
- Power in an inductor, P = I^2 * R, where R is the resistance of the inductor
- Time constant, τ = L / R
- Time taken to reach final current, t = τ * ln(I_final / I_initial)
Calculation:
- From the given data, Power (P) = 5W
- We know that Power (P) = I^2 * R
- Since the resistance of the inductor is not given, we cannot directly calculate the current. However, we can find the time constant using the formula τ = L / R.
- Given, L = 10H
- Let's assume the resistance R = 1Ω (for simplicity)
- Therefore, time constant, τ = 10 / 1 = 10s
- Now, we can calculate the time taken for the current to change from 0A to 2A using the formula t = τ * ln(I_final / I_initial)
- Substituting the values, t = 10 * ln(2 / 0) = 10 * ln(∞) = 10 * ∞ = ∞
Conclusion:
The time taken for the current in an inductor to change to 2A from 0A is theoretically infinite.
- Power in the inductor = 5W
- Inductance = 10H
- Final current = 2A
- Initial current = 0A
Formula:
- Power in an inductor, P = I^2 * R, where R is the resistance of the inductor
- Time constant, τ = L / R
- Time taken to reach final current, t = τ * ln(I_final / I_initial)
Calculation:
- From the given data, Power (P) = 5W
- We know that Power (P) = I^2 * R
- Since the resistance of the inductor is not given, we cannot directly calculate the current. However, we can find the time constant using the formula τ = L / R.
- Given, L = 10H
- Let's assume the resistance R = 1Ω (for simplicity)
- Therefore, time constant, τ = 10 / 1 = 10s
- Now, we can calculate the time taken for the current to change from 0A to 2A using the formula t = τ * ln(I_final / I_initial)
- Substituting the values, t = 10 * ln(2 / 0) = 10 * ln(∞) = 10 * ∞ = ∞
Conclusion:
The time taken for the current in an inductor to change to 2A from 0A is theoretically infinite.
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Find the time taken for the current in an inductor to change to 2A from 0A if the power in the inductor is 5W. The value of inductance is 10H.a)1sb)2sc)3sd)4sCorrect answer is option 'D'. Can you explain this answer?
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