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If α,β,γ are three consecutive integers. If these integers are raised to first, second and third positive powers respectively, and added then they form a perfect square, the square root of which is equal to the sum of these integers. Also, α<β<γ. Then, γ is equals to:a)3b)14c)5d)11Correct answer is option 'C'. Can you explain this answer? for CA Foundation 2024 is part of CA Foundation preparation. The Question and answers have been prepared
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If α,β,γ are three consecutive integers. If these integers are raised to first, second and third positive powers respectively, and added then they form a perfect square, the square root of which is equal to the sum of these integers. Also, α<β<γ. Then, γ is equals to:a)3b)14c)5d)11Correct answer is option 'C'. Can you explain this answer?, a detailed solution for If α,β,γ are three consecutive integers. If these integers are raised to first, second and third positive powers respectively, and added then they form a perfect square, the square root of which is equal to the sum of these integers. Also, α<β<γ. Then, γ is equals to:a)3b)14c)5d)11Correct answer is option 'C'. Can you explain this answer? has been provided alongside types of If α,β,γ are three consecutive integers. If these integers are raised to first, second and third positive powers respectively, and added then they form a perfect square, the square root of which is equal to the sum of these integers. Also, α<β<γ. Then, γ is equals to:a)3b)14c)5d)11Correct answer is option 'C'. Can you explain this answer? theory, EduRev gives you an
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