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In conversion of lime-stone to lime, CaCO3 (s) → CaO(s)+ CO2(g) the values of ΔH° and ΔS° are + 179.1 kJ mol-1 and 160.2 J/K respectively at 298 K and 1 bar. Assuming that ΔH° and ΔS° do not change with temperature, temperature above which conversion of limestone to lime will be spontaneous is [2007]a)1118 Kb)1008 Kc)1200 Kd)845 K.Correct answer is option 'A'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about In conversion of lime-stone to lime, CaCO3 (s) → CaO(s)+ CO2(g) the values of ΔH° and ΔS° are + 179.1 kJ mol-1 and 160.2 J/K respectively at 298 K and 1 bar. Assuming that ΔH° and ΔS° do not change with temperature, temperature above which conversion of limestone to lime will be spontaneous is [2007]a)1118 Kb)1008 Kc)1200 Kd)845 K.Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In conversion of lime-stone to lime, CaCO3 (s) → CaO(s)+ CO2(g) the values of ΔH° and ΔS° are + 179.1 kJ mol-1 and 160.2 J/K respectively at 298 K and 1 bar. Assuming that ΔH° and ΔS° do not change with temperature, temperature above which conversion of limestone to lime will be spontaneous is [2007]a)1118 Kb)1008 Kc)1200 Kd)845 K.Correct answer is option 'A'. Can you explain this answer?.

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Here you can find the meaning of In conversion of lime-stone to lime, CaCO3 (s) → CaO(s)+ CO2(g) the values of ΔH° and ΔS° are + 179.1 kJ mol-1 and 160.2 J/K respectively at 298 K and 1 bar. Assuming that ΔH° and ΔS° do not change with temperature, temperature above which conversion of limestone to lime will be spontaneous is [2007]a)1118 Kb)1008 Kc)1200 Kd)845 K.Correct answer is option 'A'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of In conversion of lime-stone to lime, CaCO3 (s) → CaO(s)+ CO2(g) the values of ΔH° and ΔS° are + 179.1 kJ mol-1 and 160.2 J/K respectively at 298 K and 1 bar. Assuming that ΔH° and ΔS° do not change with temperature, temperature above which conversion of limestone to lime will be spontaneous is [2007]a)1118 Kb)1008 Kc)1200 Kd)845 K.Correct answer is option 'A'. Can you explain this answer?, a detailed solution for In conversion of lime-stone to lime, CaCO3 (s) → CaO(s)+ CO2(g) the values of ΔH° and ΔS° are + 179.1 kJ mol-1 and 160.2 J/K respectively at 298 K and 1 bar. Assuming that ΔH° and ΔS° do not change with temperature, temperature above which conversion of limestone to lime will be spontaneous is [2007]a)1118 Kb)1008 Kc)1200 Kd)845 K.Correct answer is option 'A'. Can you explain this answer? has been provided alongside types of In conversion of lime-stone to lime, CaCO3 (s) → CaO(s)+ CO2(g) the values of ΔH° and ΔS° are + 179.1 kJ mol-1 and 160.2 J/K respectively at 298 K and 1 bar. Assuming that ΔH° and ΔS° do not change with temperature, temperature above which conversion of limestone to lime will be spontaneous is [2007]a)1118 Kb)1008 Kc)1200 Kd)845 K.Correct answer is option 'A'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice In conversion of lime-stone to lime, CaCO3 (s) → CaO(s)+ CO2(g) the values of ΔH° and ΔS° are + 179.1 kJ mol-1 and 160.2 J/K respectively at 298 K and 1 bar. Assuming that ΔH° and ΔS° do not change with temperature, temperature above which conversion of limestone to lime will be spontaneous is [2007]a)1118 Kb)1008 Kc)1200 Kd)845 K.Correct answer is option 'A'. Can you explain this answer? tests, examples and also practice JEE tests.