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The state of plane stress at a point in a loaded member is given by:
sx = + 800 MPa
sy = + 200 MPa
txy = ± 400 MPa
The maximum principal stress and maximum shear stress are given by:
- a)smax = 800 MPa and tmax = 400 MPa
- b)smax = 800 MPa and tmax = 500 MPa
- c)smax = 1000 MPa and tmax = 500 MPa
- d)smax = 1000 MPa and tmax = 400 MPa
Correct answer is option 'C'. Can you explain this answer?
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The state of plane stress at a point in a loaded member is given by:sx...
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The state of plane stress at a point in a loaded member is given by:sx...
The given problem states that the state of plane stress at a point in a loaded member is given by:
σx = 800 MPa
σy = 200 MPa
τxy = 400 MPa
To find the maximum principal stress (σmax) and maximum shear stress (τmax), we can use the following equations:
σmax = (σx + σy)/2 + √(((σx - σy)/2)^2 + τxy^2)
τmax = √(((σx - σy)/2)^2 + τxy^2)
Let's calculate the values:
σmax = (800 + 200)/2 + √(((800 - 200)/2)^2 + 400^2)
= 1000 MPa
τmax = √(((800 - 200)/2)^2 + 400^2)
= √((300)^2 + 400^2)
= √(90000 + 160000)
= √250000
= 500 MPa
Therefore, the maximum principal stress (σmax) is 1000 MPa and the maximum shear stress (τmax) is 500 MPa.
Hence, the correct answer is option (c): σmax = 1000 MPa and τmax = 500 MPa.
σx = 800 MPa
σy = 200 MPa
τxy = 400 MPa
To find the maximum principal stress (σmax) and maximum shear stress (τmax), we can use the following equations:
σmax = (σx + σy)/2 + √(((σx - σy)/2)^2 + τxy^2)
τmax = √(((σx - σy)/2)^2 + τxy^2)
Let's calculate the values:
σmax = (800 + 200)/2 + √(((800 - 200)/2)^2 + 400^2)
= 1000 MPa
τmax = √(((800 - 200)/2)^2 + 400^2)
= √((300)^2 + 400^2)
= √(90000 + 160000)
= √250000
= 500 MPa
Therefore, the maximum principal stress (σmax) is 1000 MPa and the maximum shear stress (τmax) is 500 MPa.
Hence, the correct answer is option (c): σmax = 1000 MPa and τmax = 500 MPa.
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The state of plane stress at a point in a loaded member is given by:sx = + 800 MPasy = + 200 MPatxy = ± 400 MPaThe maximum principal stress and maximum shear stress are given by:a)smax = 800 MPa and tmax = 400 MPab)smax = 800 MPa and tmax = 500 MPac)smax = 1000 MPa and tmax = 500 MPad)smax = 1000 MPa and tmax = 400 MPaCorrect answer is option 'C'. Can you explain this answer?
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The state of plane stress at a point in a loaded member is given by:sx = + 800 MPasy = + 200 MPatxy = ± 400 MPaThe maximum principal stress and maximum shear stress are given by:a)smax = 800 MPa and tmax = 400 MPab)smax = 800 MPa and tmax = 500 MPac)smax = 1000 MPa and tmax = 500 MPad)smax = 1000 MPa and tmax = 400 MPaCorrect answer is option 'C'. Can you explain this answer? for Civil Engineering (CE) 2025 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about The state of plane stress at a point in a loaded member is given by:sx = + 800 MPasy = + 200 MPatxy = ± 400 MPaThe maximum principal stress and maximum shear stress are given by:a)smax = 800 MPa and tmax = 400 MPab)smax = 800 MPa and tmax = 500 MPac)smax = 1000 MPa and tmax = 500 MPad)smax = 1000 MPa and tmax = 400 MPaCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The state of plane stress at a point in a loaded member is given by:sx = + 800 MPasy = + 200 MPatxy = ± 400 MPaThe maximum principal stress and maximum shear stress are given by:a)smax = 800 MPa and tmax = 400 MPab)smax = 800 MPa and tmax = 500 MPac)smax = 1000 MPa and tmax = 500 MPad)smax = 1000 MPa and tmax = 400 MPaCorrect answer is option 'C'. Can you explain this answer?.
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Solutions for The state of plane stress at a point in a loaded member is given by:sx = + 800 MPasy = + 200 MPatxy = ± 400 MPaThe maximum principal stress and maximum shear stress are given by:a)smax = 800 MPa and tmax = 400 MPab)smax = 800 MPa and tmax = 500 MPac)smax = 1000 MPa and tmax = 500 MPad)smax = 1000 MPa and tmax = 400 MPaCorrect answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for Civil Engineering (CE).
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