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A ring having a cross-sectional area of 500 mm2, a circumference of 400 mm and ϕ=800microWb has a coil of 200 turns wound around it. Calculate the flux density of the ring.
  • a)
    1.6T
  • b)
    2.6T
  • c)
    3.6T
  • d)
    4.6T
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
A ring having a cross-sectional area of 500 mm2, a circumference of 40...
From the given question:
Flux density= 800*10-6/500*106=1.6 Wb/m2.
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Most Upvoted Answer
A ring having a cross-sectional area of 500 mm2, a circumference of 40...
Given data:
Cross-sectional area of the ring = 500 mm²
Circumference of the ring = 400 mm
Flux linked with the ring = 800 µWb
Number of turns in the coil = 200

Formula used:
Flux density (B) = flux (Φ) / area (A)
Flux (Φ) = Number of turns (N) x flux density (B) x area (A)
Circumference (C) = π x diameter (d)

Calculation:
Circumference (C) = π x diameter (d)
⇒ 400 = π x d
⇒ d = 400 / π
⇒ d = 127.3 mm (approx.)

Area (A) = π x (d/2)²
⇒ A = π x (127.3/2)²
⇒ A = 50000 mm²

Flux (Φ) = Number of turns (N) x flux density (B) x area (A)
⇒ 800 x 10^-6 = 200 x B x 50000
⇒ B = 1.6 T (approx.)

Therefore, the flux density of the ring is 1.6 T (Tesla). Hence, option (a) is the correct answer.
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Community Answer
A ring having a cross-sectional area of 500 mm2, a circumference of 40...
1.6
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A ring having a cross-sectional area of 500 mm2, a circumference of 400 mm and ϕ=800microWb has a coil of 200 turns wound around it. Calculate the flux density of the ring.a)1.6Tb)2.6Tc)3.6Td)4.6TCorrect answer is option 'A'. Can you explain this answer?
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