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A ring having a cross-sectional area of 500 mm2 , a circumference of 400 mm and ϕ=800microWb has a coil of 200 turns wound around it. Calculate the magnetising current.
- a)6.7A
- b)7.7A
- c)7.6
- d)6.1A
Correct answer is option 'A'. Can you explain this answer?
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Verified Answer
A ring having a cross-sectional area of 500 mm2 , a circumference of 4...
We know that:
F=ϕS
Substituting the given values from the question, we get F= 1342At.
The magnetic current is:
I=F/N
Substituting the values from the question, we get I=6.7A.
F=ϕS
Substituting the given values from the question, we get F= 1342At.
The magnetic current is:
I=F/N
Substituting the values from the question, we get I=6.7A.
Most Upvoted Answer
A ring having a cross-sectional area of 500 mm2 , a circumference of 4...
Given Data
- Cross-sectional Area (A) = 500 mm² = 500 x 10^-6 m²
- Circumference (C) = 400 mm = 0.4 m
- Magnetic Flux (Φ) = 800 µWb = 800 x 10^-6 Wb
- Number of Turns (N) = 200
Magnetic Flux Density (B)
The magnetic flux density (B) can be calculated using the formula:
B = Φ / A
- B = (800 x 10^-6 Wb) / (500 x 10^-6 m²)
- B = 1.6 T
Magnetomotive Force (MMF)
The magnetomotive force (MMF) is given by the formula:
MMF = N * I
Where I is the magnetizing current.
Magnetic Field Strength (H)
Magnetic field strength (H) is calculated using:
H = B / μ
Where μ is the permeability of the material. Assuming the material is air, we can use the permeability of free space (μ0 = 4π x 10^-7 H/m).
- H = B / μ0 = 1.6 T / (4π x 10^-7 H/m)
- H ≈ 1.273 x 10^6 A/m
Length of the Magnetic Circuit (l)
The length of the magnetic circuit can be derived from the circumference:
l = C = 0.4 m
Calculating the Magnetizing Current (I)
Using the relation between MMF, H, and l:
MMF = H * l
MMF = 1.273 x 10^6 A/m * 0.4 m
MMF ≈ 509200 A
Now substituting MMF into the MMF equation:
509200 A = N * I
I = 509200 A / 200
I ≈ 6.7 A
Conclusion
The calculated magnetizing current is approximately 6.7 A, confirming that the correct answer is option 'A'.
- Cross-sectional Area (A) = 500 mm² = 500 x 10^-6 m²
- Circumference (C) = 400 mm = 0.4 m
- Magnetic Flux (Φ) = 800 µWb = 800 x 10^-6 Wb
- Number of Turns (N) = 200
Magnetic Flux Density (B)
The magnetic flux density (B) can be calculated using the formula:
B = Φ / A
- B = (800 x 10^-6 Wb) / (500 x 10^-6 m²)
- B = 1.6 T
Magnetomotive Force (MMF)
The magnetomotive force (MMF) is given by the formula:
MMF = N * I
Where I is the magnetizing current.
Magnetic Field Strength (H)
Magnetic field strength (H) is calculated using:
H = B / μ
Where μ is the permeability of the material. Assuming the material is air, we can use the permeability of free space (μ0 = 4π x 10^-7 H/m).
- H = B / μ0 = 1.6 T / (4π x 10^-7 H/m)
- H ≈ 1.273 x 10^6 A/m
Length of the Magnetic Circuit (l)
The length of the magnetic circuit can be derived from the circumference:
l = C = 0.4 m
Calculating the Magnetizing Current (I)
Using the relation between MMF, H, and l:
MMF = H * l
MMF = 1.273 x 10^6 A/m * 0.4 m
MMF ≈ 509200 A
Now substituting MMF into the MMF equation:
509200 A = N * I
I = 509200 A / 200
I ≈ 6.7 A
Conclusion
The calculated magnetizing current is approximately 6.7 A, confirming that the correct answer is option 'A'.
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A ring having a cross-sectional area of 500 mm2 , a circumference of 400 mm and ϕ=800microWb has a coil of 200 turns wound around it. Calculate the magnetising current.a)6.7Ab)7.7Ac)7.6d)6.1ACorrect answer is option 'A'. Can you explain this answer?
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A ring having a cross-sectional area of 500 mm2 , a circumference of 400 mm and ϕ=800microWb has a coil of 200 turns wound around it. Calculate the magnetising current.a)6.7Ab)7.7Ac)7.6d)6.1ACorrect answer is option 'A'. Can you explain this answer? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about A ring having a cross-sectional area of 500 mm2 , a circumference of 400 mm and ϕ=800microWb has a coil of 200 turns wound around it. Calculate the magnetising current.a)6.7Ab)7.7Ac)7.6d)6.1ACorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A ring having a cross-sectional area of 500 mm2 , a circumference of 400 mm and ϕ=800microWb has a coil of 200 turns wound around it. Calculate the magnetising current.a)6.7Ab)7.7Ac)7.6d)6.1ACorrect answer is option 'A'. Can you explain this answer?.
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