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A ring having a cross-sectional area of 500 mm2 , a circumference of 400 mm and ϕ=800microWb has a coil of 200 turns wound around it. Calculate the magnetising current.
- a)6.7A
- b)7.7A
- c)7.6
- d)6.1A
Correct answer is option 'A'. Can you explain this answer?
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Verified Answer
A ring having a cross-sectional area of 500 mm2 , a circumference of 4...
We know that:
F=ϕS
Substituting the given values from the question, we get F= 1342At.
The magnetic current is:
I=F/N
Substituting the values from the question, we get I=6.7A.
F=ϕS
Substituting the given values from the question, we get F= 1342At.
The magnetic current is:
I=F/N
Substituting the values from the question, we get I=6.7A.
Most Upvoted Answer
A ring having a cross-sectional area of 500 mm2 , a circumference of 4...
Given Data
- Cross-sectional Area (A) = 500 mm² = 500 x 10^-6 m²
- Circumference (C) = 400 mm = 0.4 m
- Magnetic Flux (Φ) = 800 µWb = 800 x 10^-6 Wb
- Number of Turns (N) = 200
Magnetic Flux Density (B)
The magnetic flux density (B) can be calculated using the formula:
B = Φ / A
- B = (800 x 10^-6 Wb) / (500 x 10^-6 m²)
- B = 1.6 T
Magnetomotive Force (MMF)
The magnetomotive force (MMF) is given by the formula:
MMF = N * I
Where I is the magnetizing current.
Magnetic Field Strength (H)
Magnetic field strength (H) is calculated using:
H = B / μ
Where μ is the permeability of the material. Assuming the material is air, we can use the permeability of free space (μ0 = 4π x 10^-7 H/m).
- H = B / μ0 = 1.6 T / (4π x 10^-7 H/m)
- H ≈ 1.273 x 10^6 A/m
Length of the Magnetic Circuit (l)
The length of the magnetic circuit can be derived from the circumference:
l = C = 0.4 m
Calculating the Magnetizing Current (I)
Using the relation between MMF, H, and l:
MMF = H * l
MMF = 1.273 x 10^6 A/m * 0.4 m
MMF ≈ 509200 A
Now substituting MMF into the MMF equation:
509200 A = N * I
I = 509200 A / 200
I ≈ 6.7 A
Conclusion
The calculated magnetizing current is approximately 6.7 A, confirming that the correct answer is option 'A'.
- Cross-sectional Area (A) = 500 mm² = 500 x 10^-6 m²
- Circumference (C) = 400 mm = 0.4 m
- Magnetic Flux (Φ) = 800 µWb = 800 x 10^-6 Wb
- Number of Turns (N) = 200
Magnetic Flux Density (B)
The magnetic flux density (B) can be calculated using the formula:
B = Φ / A
- B = (800 x 10^-6 Wb) / (500 x 10^-6 m²)
- B = 1.6 T
Magnetomotive Force (MMF)
The magnetomotive force (MMF) is given by the formula:
MMF = N * I
Where I is the magnetizing current.
Magnetic Field Strength (H)
Magnetic field strength (H) is calculated using:
H = B / μ
Where μ is the permeability of the material. Assuming the material is air, we can use the permeability of free space (μ0 = 4π x 10^-7 H/m).
- H = B / μ0 = 1.6 T / (4π x 10^-7 H/m)
- H ≈ 1.273 x 10^6 A/m
Length of the Magnetic Circuit (l)
The length of the magnetic circuit can be derived from the circumference:
l = C = 0.4 m
Calculating the Magnetizing Current (I)
Using the relation between MMF, H, and l:
MMF = H * l
MMF = 1.273 x 10^6 A/m * 0.4 m
MMF ≈ 509200 A
Now substituting MMF into the MMF equation:
509200 A = N * I
I = 509200 A / 200
I ≈ 6.7 A
Conclusion
The calculated magnetizing current is approximately 6.7 A, confirming that the correct answer is option 'A'.
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A ring having a cross-sectional area of 500 mm2 , a circumference of 400 mm and ϕ=800microWb has a coil of 200 turns wound around it. Calculate the magnetising current.a)6.7Ab)7.7Ac)7.6d)6.1ACorrect answer is option 'A'. Can you explain this answer?
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