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A block of 1 kg is stopped aganist a wall by aplying a force F perpendicular to the wall. If μ = 0.2 then minimum value of F will be
- a)980 N
- b)49 N
- c)98 N
- d)490 N
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
A block of 1 kg is stopped aganist a wall by aplying a force F perpend...
Answer : 49 N
explanation : friction is the force resisting the relative motion of two solid surface. see figure, block has tendency to move downward with respect to wall.so, friction force must be applied upward as shown in figure.
a force F is applied perpendicularly on the block. Let normal reaction acts between the block and wall is N.
at equilibrium,
F = N...(1)
and fr = mg = 1kg x 9.8 m/s^2 = 9.8N
as we know, friction = μN, where μ is coefficient of friction.
so, 9.8 = 0.2 x N
or, N = 9.8/0.2 = 49
from equation (1),
F = 49N
hence, minimum value of F will be 49N
explanation : friction is the force resisting the relative motion of two solid surface. see figure, block has tendency to move downward with respect to wall.so, friction force must be applied upward as shown in figure.
a force F is applied perpendicularly on the block. Let normal reaction acts between the block and wall is N.
at equilibrium,
F = N...(1)
and fr = mg = 1kg x 9.8 m/s^2 = 9.8N
as we know, friction = μN, where μ is coefficient of friction.
so, 9.8 = 0.2 x N
or, N = 9.8/0.2 = 49
from equation (1),
F = 49N
hence, minimum value of F will be 49N
Most Upvoted Answer
A block of 1 kg is stopped aganist a wall by aplying a force F perpend...
The coefficient of static friction between the block and the wall is μ, then the maximum force that can be applied to keep the block stationary is given by:
F_max = μmg
where m is the mass of the block (1 kg), g is the acceleration due to gravity (9.8 m/s^2), and μ is the coefficient of static friction.
In this case, the maximum force that can be applied is:
F_max = 0.4 x 1 kg x 9.8 m/s^2 = 3.92 N
Therefore, if the force applied to the block is greater than 3.92 N, the block will start moving away from the wall.
F_max = μmg
where m is the mass of the block (1 kg), g is the acceleration due to gravity (9.8 m/s^2), and μ is the coefficient of static friction.
In this case, the maximum force that can be applied is:
F_max = 0.4 x 1 kg x 9.8 m/s^2 = 3.92 N
Therefore, if the force applied to the block is greater than 3.92 N, the block will start moving away from the wall.
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