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The following acids have been arranged in the order of decreasing acid strength. Identify the correct order.
ClOH (I), BrOH(II), IOH(III)
- a)I > II > III
- b)II > I >III
- c)III > II > I
- d)I > III > II
Correct answer is option 'A'. Can you explain this answer?
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Verified Answer
The following acids have been arranged in the order of decreasing acid...
Among oxyacids of halogens, if there are same number of
oxygens bonded to central atom, higher the
electronegativity of halogen, stronger the acid. Hence,
IOH<BrOH<ClOH
IOH<BrOH<ClOH
Most Upvoted Answer
The following acids have been arranged in the order of decreasing acid...
Explanation:
Acid strength depends on the stability of the conjugate base formed after the acid donates a proton. The more stable the conjugate base, the stronger the acid.
- IOH (III): Iodine is less electronegative than chlorine and bromine, so the conjugate base (IO-) is more stable due to lower electronegativity. Hence, IOH is the strongest acid among the three.
- BrOH (II): Bromine is more electronegative than iodine but less electronegative than chlorine. Therefore, the conjugate base (Br-) is less stable compared to IO-, making BrOH the second strongest acid.
- ClOH (I): Chlorine is the most electronegative among the three halogens, resulting in a less stable conjugate base (Cl-). Thus, ClOH is the weakest acid in the series.
Therefore, the correct order of decreasing acid strength is:
I > II > III (ClOH > BrOH > IOH)
Acid strength depends on the stability of the conjugate base formed after the acid donates a proton. The more stable the conjugate base, the stronger the acid.
- IOH (III): Iodine is less electronegative than chlorine and bromine, so the conjugate base (IO-) is more stable due to lower electronegativity. Hence, IOH is the strongest acid among the three.
- BrOH (II): Bromine is more electronegative than iodine but less electronegative than chlorine. Therefore, the conjugate base (Br-) is less stable compared to IO-, making BrOH the second strongest acid.
- ClOH (I): Chlorine is the most electronegative among the three halogens, resulting in a less stable conjugate base (Cl-). Thus, ClOH is the weakest acid in the series.
Therefore, the correct order of decreasing acid strength is:
I > II > III (ClOH > BrOH > IOH)
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