Consider a pipe of length 80 cm with both ends open. How many modes of oscillations of the air column are possible upto a frequency of 1450 Hz? (Take the speed of sound to be 330 m/sec.)a)2b)3c)7d)8Correct answer is option 'C'. Can you explain this answer?

Question

Answer

To find the number of modes of oscillations of the air column in a pipe, we can use the formula:

n = (2L/v) * f

where:
n = number of modes of oscillations
L = length of the pipe
v = speed of sound
f = frequency

Given:
Length of the pipe, L = 80 cm = 0.8 m
Speed of sound, v = 330 m/s
Maximum frequency, f = 1450 Hz

We can substitute these values into the formula to find the number of modes of oscillations.

Calculation:
n = (2 * 0.8) * (1450 / 330)
n = 1.536

Since we cannot have fractional modes of oscillations, we round down the value to the nearest whole number.

Therefore, the number of modes of oscillations of the air column in the pipe is 1.

However, this answer does not match any of the given options. Let's check the options again.

Options:
a) 2
b) 3
c) 7
d) 8

Since the calculated answer does not match any of the options, there might be an error in the question or options provided.

Answer

Answer

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