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If the drift velocity of holes under a field gradient of 100 V/m is 5m/sec. Their mobility is
- a)0.05
- b)0.5
- c)50
- d)500
Correct answer is option 'A'. Can you explain this answer?
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Verified Answer
If the drift velocity of holes under a field gradient of 100 V/m is 5m...
E = μ . Vd 
μ =
.
μ =.Most Upvoted Answer
If the drift velocity of holes under a field gradient of 100 V/m is 5m...
Given information:
- Drift velocity of holes under a field gradient of 100 V/m is 5 m/s.
To find:
- The mobility of the holes.
Concepts:
- Drift velocity (vd) is the average velocity of charge carriers (in this case, holes) under the influence of an electric field.
- Drift velocity is given by the equation: vd = μE, where μ is the mobility of the charge carriers and E is the electric field intensity.
- Mobility (μ) is a measure of how easily charge carriers can move in a material under the influence of an electric field.
Solution:
Given that the drift velocity (vd) of holes is 5 m/s under an electric field gradient of 100 V/m, we can use the equation vd = μE to find the mobility (μ) of the holes.
We are given:
- vd = 5 m/s
- E = 100 V/m
Substituting these values into the equation vd = μE, we get:
5 m/s = μ * 100 V/m
Calculation:
To find the mobility (μ), divide both sides of the equation by 100 V/m:
μ = (5 m/s) / (100 V/m)
Simplifying the expression, we get:
μ = 0.05 s/m²V
Therefore, the mobility of the holes is 0.05 s/m²V.
Answer:
The mobility of the holes is 0.05 s/m²V, which corresponds to option A.
- Drift velocity of holes under a field gradient of 100 V/m is 5 m/s.
To find:
- The mobility of the holes.
Concepts:
- Drift velocity (vd) is the average velocity of charge carriers (in this case, holes) under the influence of an electric field.
- Drift velocity is given by the equation: vd = μE, where μ is the mobility of the charge carriers and E is the electric field intensity.
- Mobility (μ) is a measure of how easily charge carriers can move in a material under the influence of an electric field.
Solution:
Given that the drift velocity (vd) of holes is 5 m/s under an electric field gradient of 100 V/m, we can use the equation vd = μE to find the mobility (μ) of the holes.
We are given:
- vd = 5 m/s
- E = 100 V/m
Substituting these values into the equation vd = μE, we get:
5 m/s = μ * 100 V/m
Calculation:
To find the mobility (μ), divide both sides of the equation by 100 V/m:
μ = (5 m/s) / (100 V/m)
Simplifying the expression, we get:
μ = 0.05 s/m²V
Therefore, the mobility of the holes is 0.05 s/m²V.
Answer:
The mobility of the holes is 0.05 s/m²V, which corresponds to option A.
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