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What smallest number must be added to 6036, so that the sum is completely divisible by 14?
  • a)
    12
  • b)
    17
  • c)
    21
  • d)
    23
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
What smallest number must be added to 6036, so that the sum is complet...

Required number = (14 – 2) = 12
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What smallest number must be added to 6036, so that the sum is complet...
Problem:
What smallest number must be added to 6036, so that the sum is completely divisible by 14?

Solution:

To find the smallest number that must be added to 6036 to make it completely divisible by 14, we need to find the remainder when 6036 is divided by 14.

Step 1: Finding the remainder
To find the remainder, we divide 6036 by 14 using long division:

```
_______
14 | 6036
56
-----
163
154
-----
96
84
-----
126
112
-----
14
```

Therefore, the remainder is 14.

Step 2: Determining the smallest number to be added
Since the remainder is already 14, we don't need to add any number to 6036 to make it divisible by 14. The sum of 6036 and 14 is already divisible by 14.

Therefore, the smallest number that must be added to 6036 to make it completely divisible by 14 is 0.

Conclusion:
The correct answer is option A) 0.
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