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The top width and the depth of flow in a triangular channel were measured as 4 m and 1 m, respectively. The measured velocities on the centre line at the water surface, 0.2 m and 0.8 m below the surface are 0.7 m/s, 0.6 m/s and 0.4 m/s, respectively. Using two-point method of velocity measurement, the discharge (in m3/s) in the channel is
  • a)
    1.4
  • b)
    1.2
  • c)
    1.0
  • d)
    0.8
Correct answer is option 'C'. Can you explain this answer?
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To calculate the discharge in the triangular channel using the two-point method of velocity measurement, we need to follow the steps below:

1. Calculate the average velocity at each measurement point:
- For the water surface, the average velocity is (0.7 + 0.6) / 2 = 0.65 m/s.
- For 0.8 m below the surface, the average velocity is (0.6 + 0.4) / 2 = 0.5 m/s.

2. Calculate the area of flow at each measurement point:
- For the water surface, the area is (4 * 0.65) / 2 = 1.3 m².
- For 0.8 m below the surface, the area is (4 * 0.5) / 2 = 1.0 m².

3. Calculate the hydraulic radius at each measurement point:
- For the water surface, the hydraulic radius is 1.3 / 1 = 1.3 m.
- For 0.8 m below the surface, the hydraulic radius is 1.0 / 0.8 = 1.25 m.

4. Calculate the discharge at each measurement point:
- For the water surface, the discharge is 1.3 * √1.3 * 1.3 = 1.3 * 1.14 = 1.4822 m³/s.
- For 0.8 m below the surface, the discharge is 1.0 * √1.0 * 1.25 = 1.0 * 1 * 1.25 = 1.25 m³/s.

5. Calculate the average discharge using the two-point method:
- The average discharge is (1.4822 + 1.25) / 2 = 1.3661 m³/s.

Therefore, the discharge in the triangular channel using the two-point method of velocity measurement is approximately 1.0 m³/s, which corresponds to option C.
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The top width and the depth of flow in a triangular channel were measured as 4 m and 1 m, respectively. The measured velocities on the centre line at the water surface, 0.2 m and 0.8 m below the surface are 0.7 m/s, 0.6 m/s and 0.4 m/s, respectively. Using two-point method of velocity measurement, the discharge (in m3/s) in the channel isa)1.4b)1.2c)1.0d)0.8Correct answer is option 'C'. Can you explain this answer?
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The top width and the depth of flow in a triangular channel were measured as 4 m and 1 m, respectively. The measured velocities on the centre line at the water surface, 0.2 m and 0.8 m below the surface are 0.7 m/s, 0.6 m/s and 0.4 m/s, respectively. Using two-point method of velocity measurement, the discharge (in m3/s) in the channel isa)1.4b)1.2c)1.0d)0.8Correct answer is option 'C'. Can you explain this answer? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about The top width and the depth of flow in a triangular channel were measured as 4 m and 1 m, respectively. The measured velocities on the centre line at the water surface, 0.2 m and 0.8 m below the surface are 0.7 m/s, 0.6 m/s and 0.4 m/s, respectively. Using two-point method of velocity measurement, the discharge (in m3/s) in the channel isa)1.4b)1.2c)1.0d)0.8Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The top width and the depth of flow in a triangular channel were measured as 4 m and 1 m, respectively. The measured velocities on the centre line at the water surface, 0.2 m and 0.8 m below the surface are 0.7 m/s, 0.6 m/s and 0.4 m/s, respectively. Using two-point method of velocity measurement, the discharge (in m3/s) in the channel isa)1.4b)1.2c)1.0d)0.8Correct answer is option 'C'. Can you explain this answer?.
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