Colligative property measurement is one of the techniques used in the measurement of chemical quantities with reasonable accuracy.If a 40.65 gm sample of K2SO4 and BaSO4 is dissolved in 900 gm of pure water to form a solution A at 57C, its vapour pressure is found to be 39.6 torr while vapour pressure of pure water at 57C is 40 torr. Density of solution A is 1.24 gm/ml.In a different experiment when small amount of pure BaSO4 is mixed with water at 57C it gives the osmotic rise of 4.05 x 10-5 atm. (R = 0.082 Lt.-atm/mol-K ; K = 39, Ba = 137, S = 32, 0 = 16)Percentage of K2SO4 in the sample is : .a) 65.75%b) 71.34%c) 60.35%d) 78.74%Correct answer is option 'B'. Can you explain this answer?

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Colligative property measurement is one of the techniques used in the measurement of chemical quantities with reasonable accuracy.

If a 40.65 gm sample of K₂SO₄ and BaSO₄ is dissolved in 900 gm of pure water to form a solution 'A' at 57°C, its vapour pressure is found to be 39.6 torr while vapour pressure of pure water at 57°C is 40 torr. Density of solution A is 1.24 gm/ml.

In a different experiment when small amount of pure BaSO₄ is mixed with water at 5⁷°C it gives the osmotic rise of 4.05 x 10^-5 atm. (R = 0.082 Lt.-atm/mol-K ; K = 39, Ba = 137, S = 32, 0 = 16)

Percentage of K₂SO₄ in the sample is : .

a)
65.75%
b)
71.34%
c)
60.35%
d)
78.74%

Correct answer is option 'B'. Can you explain this answer?

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Colligative property measurement is one of the techniques used in the ...

\frac{40 - 39.6}{39.6} = \frac{3 \times \frac{x}{174}}{50}

x=29.29 g

% = \frac{29.29}{40.65} \times 100 = 72 %

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Colligative property measurement is one of the techniques used in the ...

To find the percentage of K2SO4 in the sample, we can use the colligative property measurements of the solution. The colligative properties depend on the number of solute particles in the solution, rather than their chemical identity. In this case, we will use the vapor pressure and osmotic pressure measurements to determine the percentage of K2SO4 in the sample.

1. Calculation of moles of BaSO4:
First, we need to calculate the moles of BaSO4 in the solution. The molar mass of BaSO4 is calculated as follows:
Molar mass of BaSO4 = (Ba atomic mass) + (S atomic mass) + 4*(O atomic mass)
= (1*137) + (1*32) + 4*(16)
= 137 + 32 + 64
= 233 g/mol

The moles of BaSO4 can be calculated using the given mass and molar mass:
Moles of BaSO4 = (mass of BaSO4) / (molar mass of BaSO4)
= 40.65 g / 233 g/mol
≈ 0.1748 mol

2. Calculation of moles of K2SO4:
Next, we need to calculate the moles of K2SO4 in the solution. Using the same method as above, we find:
Molar mass of K2SO4 = (2*(K atomic mass)) + (1*S atomic mass) + 4*(O atomic mass)
= (2*39) + 32 + 4*(16)
= 78 + 32 + 64
= 174 g/mol

The moles of K2SO4 can be calculated using the given mass and molar mass:
Moles of K2SO4 = (mass of K2SO4) / (molar mass of K2SO4)
= (total mass of sample) - (mass of BaSO4) / (molar mass of K2SO4)
= (40.65 g + mass of water) - (40.65 g) / (174 g/mol)
≈ (40.65 g + 900 g) / (174 g/mol)
≈ 5.46 mol

3. Calculation of moles of water:
Since the density of solution A is given as 1.24 g/mL, we can calculate the volume of water using the given mass and density:
Volume of water = (mass of water) / (density of water)
= 900 g / (1.24 g/mL)
≈ 725.81 mL

The moles of water can be calculated using the given volume and molar volume at standard temperature and pressure (STP):
Moles of water = (volume of water) / (molar volume at STP)
= 725.81 mL / (22.4 L/mol)
≈ 32.43 mol

4. Calculation of vapor pressure depression:
The vapor pressure of the solution is lower than that of pure water due to the presence of solute particles. The vapor pressure depression can be calculated using Raoult's law:
ΔP = (moles of solute) / (total moles) * (vapor pressure of pure solvent)

Here, the total mo

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Colligative property measurement is one of the techniques used in the measurement of chemical quantities with reasonable accuracy.If a 40.65 gm sample of K2SO4 and BaSO4 is dissolved in 900 gm of pure water to form a solution A at 57C, its vapour pressure is found to be 39.6 torr while vapour pressure of pure water at 57C is 40 torr. Density of solution A is 1.24 gm/ml.In a different experiment when small amount of pure BaSO4 is mixed with water at 57C it gives the osmotic rise of 4.05 x 10-5 atm. (R = 0.082 Lt.-atm/mol-K ; K = 39, Ba = 137, S = 32, 0 = 16)Q.Boiling point of solution A is (Kb water = 0.54 K-kg/mol)

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Colligative property measurement is one of the techniques used in the measurement of chemical quantities with reasonable accuracy.If a 40.65 gm sample of K2SO4 and BaSO4 is dissolved in 900 gm of pure water to form a solution 'A' at 57°C, its vapour pressure is found to be 39.6 torr while vapour pressure of pure water at 57°C is 40 torr. Density of solution A is 1.24 gm/ml.In a different experiment when small amount of pure BaSO4 is mixed with water at 57°C it gives the osmotic rise of 4.05 x 10-5 atm. (R = 0.082 Lt.-atm/mol-K ; K = 39, Ba = 137, S = 32, 0 = 16)Percentage of K2SO4 in the sample is : .a) 65.75%b) 71.34%c) 60.35%d) 78.74%Correct answer is option 'B'. Can you explain this answer?

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Colligative property measurement is one of the techniques used in the measurement of chemical quantities with reasonable accuracy.If a 40.65 gm sample of K2SO4 and BaSO4 is dissolved in 900 gm of pure water to form a solution 'A' at 57°C, its vapour pressure is found to be 39.6 torr while vapour pressure of pure water at 57°C is 40 torr. Density of solution A is 1.24 gm/ml.In a different experiment when small amount of pure BaSO4 is mixed with water at 57°C it gives the osmotic rise of 4.05 x 10-5 atm. (R = 0.082 Lt.-atm/mol-K ; K = 39, Ba = 137, S = 32, 0 = 16)Percentage of K2SO4 in the sample is : .a) 65.75%b) 71.34%c) 60.35%d) 78.74%Correct answer is option 'B'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Colligative property measurement is one of the techniques used in the measurement of chemical quantities with reasonable accuracy.If a 40.65 gm sample of K2SO4 and BaSO4 is dissolved in 900 gm of pure water to form a solution 'A' at 57°C, its vapour pressure is found to be 39.6 torr while vapour pressure of pure water at 57°C is 40 torr. Density of solution A is 1.24 gm/ml.In a different experiment when small amount of pure BaSO4 is mixed with water at 57°C it gives the osmotic rise of 4.05 x 10-5 atm. (R = 0.082 Lt.-atm/mol-K ; K = 39, Ba = 137, S = 32, 0 = 16)Percentage of K2SO4 in the sample is : .a) 65.75%b) 71.34%c) 60.35%d) 78.74%Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Colligative property measurement is one of the techniques used in the measurement of chemical quantities with reasonable accuracy.If a 40.65 gm sample of K2SO4 and BaSO4 is dissolved in 900 gm of pure water to form a solution 'A' at 57°C, its vapour pressure is found to be 39.6 torr while vapour pressure of pure water at 57°C is 40 torr. Density of solution A is 1.24 gm/ml.In a different experiment when small amount of pure BaSO4 is mixed with water at 57°C it gives the osmotic rise of 4.05 x 10-5 atm. (R = 0.082 Lt.-atm/mol-K ; K = 39, Ba = 137, S = 32, 0 = 16)Percentage of K2SO4 in the sample is : .a) 65.75%b) 71.34%c) 60.35%d) 78.74%Correct answer is option 'B'. Can you explain this answer?.

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