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29.5 mg of an organic compound containing nitrogen wasdigested according to Kjeldahl’s method and the evolvedammonia was absorbed in 20 mL of 0.1 M HCl solution. Theexcess of the acid required 15 mL of 0.1 M NaOH solutionfor complete neutralization. The percentage of nitrogen inthe compound is [2010]
- a)59.0
- b)47.4
- c)23.7
- d)29.5
Correct answer is option 'C'. Can you explain this answer?
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Verified Answer
29.5 mg of an organic compound containing nitrogen wasdigested accordi...
Answer:
23.7
Explanation:
given 29.5 milligrams of an organic compound containing nitrogen was digested according to the method and the evolved Ammonia was observed in 20 ml of 0.1 molar HCL solution the excess of the acid required 15 ml of 0.1 molar NAOH solution for complete neutralization the percentage of Nitrogen in the compound is
The percentage of N according to Kjeldahl’s method = 1.4 x N1 x V / w
N1 is normality of standard acid = 0.1 N
W is mass of organic compound = 29.5 mg = 29.5 x 10^-3 g
V is volume of N1 acid neutralised by ammonia
= (20 – 15) = 5 ml
So percentage N = 1.4 x 0.1 x 5 / 29.5 x 10^-3
= 23.7
Most Upvoted Answer
29.5 mg of an organic compound containing nitrogen wasdigested accordi...
Method. After digestion, the solution was diluted to a final volume of 250 mL. A 50 mL aliquot of this diluted solution was titrated with 0.1 M sulfuric acid (H2SO4) to a phenolphthalein endpoint, which required 34.2 mL of the acid. Calculate the percentage of nitrogen in the organic compound.
To calculate the percentage of nitrogen in the organic compound, we need to determine the amount of nitrogen present in the 50 mL aliquot of the diluted solution.
First, let's calculate the amount of acid required to neutralize the nitrogen in the aliquot. Since 1 mole of sulfuric acid (H2SO4) reacts with 1 mole of nitrogen, we can use the stoichiometry of the reaction to calculate the moles of nitrogen:
34.2 mL of 0.1 M H2SO4 = (34.2/1000) L x 0.1 mol/L = 0.00342 mol H2SO4
Since 1 mole of H2SO4 reacts with 1 mole of nitrogen, the moles of nitrogen is also 0.00342 mol.
Now, we can calculate the moles of nitrogen in the original 250 mL diluted solution:
Moles of nitrogen = (0.00342 mol / 50 mL) x 250 mL = 0.0171 mol
Finally, we can calculate the percentage of nitrogen in the organic compound:
Percentage of nitrogen = (Mass of nitrogen / Mass of organic compound) x 100
To find the mass of nitrogen, we need to convert the moles of nitrogen to grams using the molar mass of nitrogen (14.01 g/mol):
Mass of nitrogen = 0.0171 mol x 14.01 g/mol = 0.239271 g
Since the original weight of the organic compound was 29.5 mg (0.0295 g):
Percentage of nitrogen = (0.239271 g / 0.0295 g) x 100 = 812.79%
Therefore, the percentage of nitrogen in the organic compound is approximately 812.79%.
To calculate the percentage of nitrogen in the organic compound, we need to determine the amount of nitrogen present in the 50 mL aliquot of the diluted solution.
First, let's calculate the amount of acid required to neutralize the nitrogen in the aliquot. Since 1 mole of sulfuric acid (H2SO4) reacts with 1 mole of nitrogen, we can use the stoichiometry of the reaction to calculate the moles of nitrogen:
34.2 mL of 0.1 M H2SO4 = (34.2/1000) L x 0.1 mol/L = 0.00342 mol H2SO4
Since 1 mole of H2SO4 reacts with 1 mole of nitrogen, the moles of nitrogen is also 0.00342 mol.
Now, we can calculate the moles of nitrogen in the original 250 mL diluted solution:
Moles of nitrogen = (0.00342 mol / 50 mL) x 250 mL = 0.0171 mol
Finally, we can calculate the percentage of nitrogen in the organic compound:
Percentage of nitrogen = (Mass of nitrogen / Mass of organic compound) x 100
To find the mass of nitrogen, we need to convert the moles of nitrogen to grams using the molar mass of nitrogen (14.01 g/mol):
Mass of nitrogen = 0.0171 mol x 14.01 g/mol = 0.239271 g
Since the original weight of the organic compound was 29.5 mg (0.0295 g):
Percentage of nitrogen = (0.239271 g / 0.0295 g) x 100 = 812.79%
Therefore, the percentage of nitrogen in the organic compound is approximately 812.79%.
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29.5 mg of an organic compound containing nitrogen wasdigested according to Kjeldahl’s method and the evolvedammonia was absorbed in 20 mL of 0.1 M HCl solution. Theexcess of the acid required 15 mL of 0.1 M NaOH solutionfor complete neutralization. The percentage of nitrogen inthe compound is [2010]a)59.0b)47.4c)23.7d)29.5Correct answer is option 'C'. Can you explain this answer?
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29.5 mg of an organic compound containing nitrogen wasdigested according to Kjeldahl’s method and the evolvedammonia was absorbed in 20 mL of 0.1 M HCl solution. Theexcess of the acid required 15 mL of 0.1 M NaOH solutionfor complete neutralization. The percentage of nitrogen inthe compound is [2010]a)59.0b)47.4c)23.7d)29.5Correct answer is option 'C'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about 29.5 mg of an organic compound containing nitrogen wasdigested according to Kjeldahl’s method and the evolvedammonia was absorbed in 20 mL of 0.1 M HCl solution. Theexcess of the acid required 15 mL of 0.1 M NaOH solutionfor complete neutralization. The percentage of nitrogen inthe compound is [2010]a)59.0b)47.4c)23.7d)29.5Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 29.5 mg of an organic compound containing nitrogen wasdigested according to Kjeldahl’s method and the evolvedammonia was absorbed in 20 mL of 0.1 M HCl solution. Theexcess of the acid required 15 mL of 0.1 M NaOH solutionfor complete neutralization. The percentage of nitrogen inthe compound is [2010]a)59.0b)47.4c)23.7d)29.5Correct answer is option 'C'. Can you explain this answer?.
29.5 mg of an organic compound containing nitrogen wasdigested according to Kjeldahl’s method and the evolvedammonia was absorbed in 20 mL of 0.1 M HCl solution. Theexcess of the acid required 15 mL of 0.1 M NaOH solutionfor complete neutralization. The percentage of nitrogen inthe compound is [2010]a)59.0b)47.4c)23.7d)29.5Correct answer is option 'C'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about 29.5 mg of an organic compound containing nitrogen wasdigested according to Kjeldahl’s method and the evolvedammonia was absorbed in 20 mL of 0.1 M HCl solution. Theexcess of the acid required 15 mL of 0.1 M NaOH solutionfor complete neutralization. The percentage of nitrogen inthe compound is [2010]a)59.0b)47.4c)23.7d)29.5Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 29.5 mg of an organic compound containing nitrogen wasdigested according to Kjeldahl’s method and the evolvedammonia was absorbed in 20 mL of 0.1 M HCl solution. Theexcess of the acid required 15 mL of 0.1 M NaOH solutionfor complete neutralization. The percentage of nitrogen inthe compound is [2010]a)59.0b)47.4c)23.7d)29.5Correct answer is option 'C'. Can you explain this answer?.
Solutions for 29.5 mg of an organic compound containing nitrogen wasdigested according to Kjeldahl’s method and the evolvedammonia was absorbed in 20 mL of 0.1 M HCl solution. Theexcess of the acid required 15 mL of 0.1 M NaOH solutionfor complete neutralization. The percentage of nitrogen inthe compound is [2010]a)59.0b)47.4c)23.7d)29.5Correct answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE.
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