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Suppose a circular queue of capacity (n – 1) elements is implemented with an array of n elements. Assume that the insertion and deletion operation are carried out using REAR and FRONT as array index variables, respectively. Initially, REAR = FRONT = 0. The conditions to detect queue full and queue empty are
- a)Full: (REAR+1) mod n == FRONT, empty: REAR == FRONT
- b)Full: (REAR+1) mod n == FRONT, empty: (FRONT+1) mod n == REAR
- c)Full: REAR == FRONT, empty: (REAR+1) mod n == FRONT
- d)Full: (FRONT+1) mod n == REAR, empty: REAR == FRONT
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
Suppose a circular queue of capacity (n – 1) elements is impleme...
Suppose we start filling the queue.
Let the maxQueueSize ( Capacity of the Queue) is 4.
So the size of the array which is used to implement this circular queue is 5, which is n.
So the size of the array which is used to implement this circular queue is 5, which is n.
In the begining when the queue is empty, FRONT and REAR point to 0 index in the array.
REAR represents insertion at the REAR index.
FRONT represents deletion from the FRONT index.
FRONT represents deletion from the FRONT index.
enqueue("a"); REAR = (REAR+1)%5; ( FRONT = 0, REAR = 1)
enqueue("b"); REAR = (REAR+1)%5; ( FRONT = 0, REAR = 2)
enqueue("c"); REAR = (REAR+1)%5; ( FRONT = 0, REAR = 3)
enqueue("d"); REAR = (REAR+1)%5; ( FRONT = 0, REAR = 4)
enqueue("b"); REAR = (REAR+1)%5; ( FRONT = 0, REAR = 2)
enqueue("c"); REAR = (REAR+1)%5; ( FRONT = 0, REAR = 3)
enqueue("d"); REAR = (REAR+1)%5; ( FRONT = 0, REAR = 4)
Most Upvoted Answer
Suppose a circular queue of capacity (n – 1) elements is impleme...
Understanding Circular Queue Implementation
In a circular queue implemented with an array, the main objective is to utilize space efficiently. Here’s how the conditions for detecting a full and empty queue work:
Queue Full Condition
- The circular queue is considered full when the next position of the REAR index wraps around to the FRONT index.
- This can be mathematically represented as:
(REAR + 1) mod n == FRONT
- This ensures that if you try to insert an element when REAR is at the last index, it wraps around to the beginning of the array. If this wrapped position equals FRONT, it signifies that the queue is full.
Queue Empty Condition
- A circular queue is empty when the REAR index is equal to the FRONT index.
- This condition is straightforward:
REAR == FRONT
- When both indices point to the same position, it indicates that there are no elements in the queue.
Summary of Option A
- Full: (REAR + 1) mod n == FRONT
- Empty: REAR == FRONT
This combination allows the circular queue to efficiently manage insertions and deletions without ambiguity or wasted space.
Importance of Correct Conditions
- Using the correct conditions prevents errors during queue operations.
- It ensures that the queue behaves as intended, maintaining the circular nature and optimizing space usage.
In conclusion, option A provides the correct logical framework for managing a circular queue using an array.
In a circular queue implemented with an array, the main objective is to utilize space efficiently. Here’s how the conditions for detecting a full and empty queue work:
Queue Full Condition
- The circular queue is considered full when the next position of the REAR index wraps around to the FRONT index.
- This can be mathematically represented as:
(REAR + 1) mod n == FRONT
- This ensures that if you try to insert an element when REAR is at the last index, it wraps around to the beginning of the array. If this wrapped position equals FRONT, it signifies that the queue is full.
Queue Empty Condition
- A circular queue is empty when the REAR index is equal to the FRONT index.
- This condition is straightforward:
REAR == FRONT
- When both indices point to the same position, it indicates that there are no elements in the queue.
Summary of Option A
- Full: (REAR + 1) mod n == FRONT
- Empty: REAR == FRONT
This combination allows the circular queue to efficiently manage insertions and deletions without ambiguity or wasted space.
Importance of Correct Conditions
- Using the correct conditions prevents errors during queue operations.
- It ensures that the queue behaves as intended, maintaining the circular nature and optimizing space usage.
In conclusion, option A provides the correct logical framework for managing a circular queue using an array.
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Question Description
Suppose a circular queue of capacity (n – 1) elements is implemented with an array of n elements. Assume that the insertion and deletion operation are carried out using REAR and FRONT as array index variables, respectively. Initially, REAR = FRONT = 0. The conditions to detect queue full and queue empty area)Full: (REAR+1) mod n == FRONT, empty: REAR == FRONTb)Full: (REAR+1) mod n == FRONT, empty: (FRONT+1) mod n == REARc)Full: REAR == FRONT, empty: (REAR+1) mod n == FRONTd)Full: (FRONT+1) mod n == REAR, empty: REAR == FRONTCorrect answer is option 'A'. Can you explain this answer? for Computer Science Engineering (CSE) 2025 is part of Computer Science Engineering (CSE) preparation. The Question and answers have been prepared according to the Computer Science Engineering (CSE) exam syllabus. Information about Suppose a circular queue of capacity (n – 1) elements is implemented with an array of n elements. Assume that the insertion and deletion operation are carried out using REAR and FRONT as array index variables, respectively. Initially, REAR = FRONT = 0. The conditions to detect queue full and queue empty area)Full: (REAR+1) mod n == FRONT, empty: REAR == FRONTb)Full: (REAR+1) mod n == FRONT, empty: (FRONT+1) mod n == REARc)Full: REAR == FRONT, empty: (REAR+1) mod n == FRONTd)Full: (FRONT+1) mod n == REAR, empty: REAR == FRONTCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Computer Science Engineering (CSE) 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Suppose a circular queue of capacity (n – 1) elements is implemented with an array of n elements. Assume that the insertion and deletion operation are carried out using REAR and FRONT as array index variables, respectively. Initially, REAR = FRONT = 0. The conditions to detect queue full and queue empty area)Full: (REAR+1) mod n == FRONT, empty: REAR == FRONTb)Full: (REAR+1) mod n == FRONT, empty: (FRONT+1) mod n == REARc)Full: REAR == FRONT, empty: (REAR+1) mod n == FRONTd)Full: (FRONT+1) mod n == REAR, empty: REAR == FRONTCorrect answer is option 'A'. Can you explain this answer?.
Suppose a circular queue of capacity (n – 1) elements is implemented with an array of n elements. Assume that the insertion and deletion operation are carried out using REAR and FRONT as array index variables, respectively. Initially, REAR = FRONT = 0. The conditions to detect queue full and queue empty area)Full: (REAR+1) mod n == FRONT, empty: REAR == FRONTb)Full: (REAR+1) mod n == FRONT, empty: (FRONT+1) mod n == REARc)Full: REAR == FRONT, empty: (REAR+1) mod n == FRONTd)Full: (FRONT+1) mod n == REAR, empty: REAR == FRONTCorrect answer is option 'A'. Can you explain this answer? for Computer Science Engineering (CSE) 2025 is part of Computer Science Engineering (CSE) preparation. The Question and answers have been prepared according to the Computer Science Engineering (CSE) exam syllabus. Information about Suppose a circular queue of capacity (n – 1) elements is implemented with an array of n elements. Assume that the insertion and deletion operation are carried out using REAR and FRONT as array index variables, respectively. Initially, REAR = FRONT = 0. The conditions to detect queue full and queue empty area)Full: (REAR+1) mod n == FRONT, empty: REAR == FRONTb)Full: (REAR+1) mod n == FRONT, empty: (FRONT+1) mod n == REARc)Full: REAR == FRONT, empty: (REAR+1) mod n == FRONTd)Full: (FRONT+1) mod n == REAR, empty: REAR == FRONTCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Computer Science Engineering (CSE) 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Suppose a circular queue of capacity (n – 1) elements is implemented with an array of n elements. Assume that the insertion and deletion operation are carried out using REAR and FRONT as array index variables, respectively. Initially, REAR = FRONT = 0. The conditions to detect queue full and queue empty area)Full: (REAR+1) mod n == FRONT, empty: REAR == FRONTb)Full: (REAR+1) mod n == FRONT, empty: (FRONT+1) mod n == REARc)Full: REAR == FRONT, empty: (REAR+1) mod n == FRONTd)Full: (FRONT+1) mod n == REAR, empty: REAR == FRONTCorrect answer is option 'A'. Can you explain this answer?.
Solutions for Suppose a circular queue of capacity (n – 1) elements is implemented with an array of n elements. Assume that the insertion and deletion operation are carried out using REAR and FRONT as array index variables, respectively. Initially, REAR = FRONT = 0. The conditions to detect queue full and queue empty area)Full: (REAR+1) mod n == FRONT, empty: REAR == FRONTb)Full: (REAR+1) mod n == FRONT, empty: (FRONT+1) mod n == REARc)Full: REAR == FRONT, empty: (REAR+1) mod n == FRONTd)Full: (FRONT+1) mod n == REAR, empty: REAR == FRONTCorrect answer is option 'A'. Can you explain this answer? in English & in Hindi are available as part of our courses for Computer Science Engineering (CSE).
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Suppose a circular queue of capacity (n – 1) elements is implemented with an array of n elements. Assume that the insertion and deletion operation are carried out using REAR and FRONT as array index variables, respectively. Initially, REAR = FRONT = 0. The conditions to detect queue full and queue empty area)Full: (REAR+1) mod n == FRONT, empty: REAR == FRONTb)Full: (REAR+1) mod n == FRONT, empty: (FRONT+1) mod n == REARc)Full: REAR == FRONT, empty: (REAR+1) mod n == FRONTd)Full: (FRONT+1) mod n == REAR, empty: REAR == FRONTCorrect answer is option 'A'. Can you explain this answer?, a detailed solution for Suppose a circular queue of capacity (n – 1) elements is implemented with an array of n elements. Assume that the insertion and deletion operation are carried out using REAR and FRONT as array index variables, respectively. Initially, REAR = FRONT = 0. The conditions to detect queue full and queue empty area)Full: (REAR+1) mod n == FRONT, empty: REAR == FRONTb)Full: (REAR+1) mod n == FRONT, empty: (FRONT+1) mod n == REARc)Full: REAR == FRONT, empty: (REAR+1) mod n == FRONTd)Full: (FRONT+1) mod n == REAR, empty: REAR == FRONTCorrect answer is option 'A'. Can you explain this answer? has been provided alongside types of Suppose a circular queue of capacity (n – 1) elements is implemented with an array of n elements. Assume that the insertion and deletion operation are carried out using REAR and FRONT as array index variables, respectively. Initially, REAR = FRONT = 0. The conditions to detect queue full and queue empty area)Full: (REAR+1) mod n == FRONT, empty: REAR == FRONTb)Full: (REAR+1) mod n == FRONT, empty: (FRONT+1) mod n == REARc)Full: REAR == FRONT, empty: (REAR+1) mod n == FRONTd)Full: (FRONT+1) mod n == REAR, empty: REAR == FRONTCorrect answer is option 'A'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice Suppose a circular queue of capacity (n – 1) elements is implemented with an array of n elements. Assume that the insertion and deletion operation are carried out using REAR and FRONT as array index variables, respectively. Initially, REAR = FRONT = 0. The conditions to detect queue full and queue empty area)Full: (REAR+1) mod n == FRONT, empty: REAR == FRONTb)Full: (REAR+1) mod n == FRONT, empty: (FRONT+1) mod n == REARc)Full: REAR == FRONT, empty: (REAR+1) mod n == FRONTd)Full: (FRONT+1) mod n == REAR, empty: REAR == FRONTCorrect answer is option 'A'. Can you explain this answer? tests, examples and also practice Computer Science Engineering (CSE) tests.
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