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Suppose a circular queue of capacity (n – 1) elements is implemented with an array of n elements. Assume that the insertion and deletion operation are carried out using REAR and FRONT as array index variables, respectively. Initially, REAR = FRONT = 0. The conditions to detect queue full and queue empty area)Full: (REAR+1) mod n == FRONT, empty: REAR == FRONTb)Full: (REAR+1) mod n == FRONT, empty: (FRONT+1) mod n == REARc)Full: REAR == FRONT, empty: (REAR+1) mod n == FRONTd)Full: (FRONT+1) mod n == REAR, empty: REAR == FRONTCorrect answer is option 'A'. Can you explain this answer? for Computer Science Engineering (CSE) 2024 is part of Computer Science Engineering (CSE) preparation. The Question and answers have been prepared according to the Computer Science Engineering (CSE) exam syllabus. Information about Suppose a circular queue of capacity (n – 1) elements is implemented with an array of n elements. Assume that the insertion and deletion operation are carried out using REAR and FRONT as array index variables, respectively. Initially, REAR = FRONT = 0. The conditions to detect queue full and queue empty area)Full: (REAR+1) mod n == FRONT, empty: REAR == FRONTb)Full: (REAR+1) mod n == FRONT, empty: (FRONT+1) mod n == REARc)Full: REAR == FRONT, empty: (REAR+1) mod n == FRONTd)Full: (FRONT+1) mod n == REAR, empty: REAR == FRONTCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Computer Science Engineering (CSE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Suppose a circular queue of capacity (n – 1) elements is implemented with an array of n elements. Assume that the insertion and deletion operation are carried out using REAR and FRONT as array index variables, respectively. Initially, REAR = FRONT = 0. The conditions to detect queue full and queue empty area)Full: (REAR+1) mod n == FRONT, empty: REAR == FRONTb)Full: (REAR+1) mod n == FRONT, empty: (FRONT+1) mod n == REARc)Full: REAR == FRONT, empty: (REAR+1) mod n == FRONTd)Full: (FRONT+1) mod n == REAR, empty: REAR == FRONTCorrect answer is option 'A'. Can you explain this answer?.

Solutions for Suppose a circular queue of capacity (n – 1) elements is implemented with an array of n elements. Assume that the insertion and deletion operation are carried out using REAR and FRONT as array index variables, respectively. Initially, REAR = FRONT = 0. The conditions to detect queue full and queue empty area)Full: (REAR+1) mod n == FRONT, empty: REAR == FRONTb)Full: (REAR+1) mod n == FRONT, empty: (FRONT+1) mod n == REARc)Full: REAR == FRONT, empty: (REAR+1) mod n == FRONTd)Full: (FRONT+1) mod n == REAR, empty: REAR == FRONTCorrect answer is option 'A'. Can you explain this answer? in English & in Hindi are available as part of our courses for Computer Science Engineering (CSE). Download more important topics, notes, lectures and mock test series for Computer Science Engineering (CSE) Exam by signing up for free.

Here you can find the meaning of Suppose a circular queue of capacity (n – 1) elements is implemented with an array of n elements. Assume that the insertion and deletion operation are carried out using REAR and FRONT as array index variables, respectively. Initially, REAR = FRONT = 0. The conditions to detect queue full and queue empty area)Full: (REAR+1) mod n == FRONT, empty: REAR == FRONTb)Full: (REAR+1) mod n == FRONT, empty: (FRONT+1) mod n == REARc)Full: REAR == FRONT, empty: (REAR+1) mod n == FRONTd)Full: (FRONT+1) mod n == REAR, empty: REAR == FRONTCorrect answer is option 'A'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of Suppose a circular queue of capacity (n – 1) elements is implemented with an array of n elements. Assume that the insertion and deletion operation are carried out using REAR and FRONT as array index variables, respectively. Initially, REAR = FRONT = 0. The conditions to detect queue full and queue empty area)Full: (REAR+1) mod n == FRONT, empty: REAR == FRONTb)Full: (REAR+1) mod n == FRONT, empty: (FRONT+1) mod n == REARc)Full: REAR == FRONT, empty: (REAR+1) mod n == FRONTd)Full: (FRONT+1) mod n == REAR, empty: REAR == FRONTCorrect answer is option 'A'. Can you explain this answer?, a detailed solution for Suppose a circular queue of capacity (n – 1) elements is implemented with an array of n elements. Assume that the insertion and deletion operation are carried out using REAR and FRONT as array index variables, respectively. Initially, REAR = FRONT = 0. The conditions to detect queue full and queue empty area)Full: (REAR+1) mod n == FRONT, empty: REAR == FRONTb)Full: (REAR+1) mod n == FRONT, empty: (FRONT+1) mod n == REARc)Full: REAR == FRONT, empty: (REAR+1) mod n == FRONTd)Full: (FRONT+1) mod n == REAR, empty: REAR == FRONTCorrect answer is option 'A'. Can you explain this answer? has been provided alongside types of Suppose a circular queue of capacity (n – 1) elements is implemented with an array of n elements. Assume that the insertion and deletion operation are carried out using REAR and FRONT as array index variables, respectively. Initially, REAR = FRONT = 0. The conditions to detect queue full and queue empty area)Full: (REAR+1) mod n == FRONT, empty: REAR == FRONTb)Full: (REAR+1) mod n == FRONT, empty: (FRONT+1) mod n == REARc)Full: REAR == FRONT, empty: (REAR+1) mod n == FRONTd)Full: (FRONT+1) mod n == REAR, empty: REAR == FRONTCorrect answer is option 'A'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice Suppose a circular queue of capacity (n – 1) elements is implemented with an array of n elements. Assume that the insertion and deletion operation are carried out using REAR and FRONT as array index variables, respectively. Initially, REAR = FRONT = 0. The conditions to detect queue full and queue empty area)Full: (REAR+1) mod n == FRONT, empty: REAR == FRONTb)Full: (REAR+1) mod n == FRONT, empty: (FRONT+1) mod n == REARc)Full: REAR == FRONT, empty: (REAR+1) mod n == FRONTd)Full: (FRONT+1) mod n == REAR, empty: REAR == FRONTCorrect answer is option 'A'. Can you explain this answer? tests, examples and also practice Computer Science Engineering (CSE) tests.