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A broadside array consisting of 200 cm wavelength with 10 half-wave dipole spacing 10 cm. And if each array element feeding with 1 amp. current and operating at same frequency then find the half power beamwidth
  • a)
  • b)
  • c)
    10º
  • d)
    15º
Correct answer is option 'B'. Can you explain this answer?
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To find the half power beamwidth (HPBW) of the broadside array, we need to calculate the beamwidth in radians and convert it to degrees.

The formula for calculating the HPBW in radians is:

HPBW (radians) = 2 * sin^(-1) (1.22 * λ / D)

Where:
λ = wavelength = 200 cm = 2 meters
D = spacing between array elements = 10 cm = 0.1 meters

Plugging in the values:

HPBW (radians) = 2 * sin^(-1) (1.22 * 2 / 0.1)
= 2 * sin^(-1) (24.4)
≈ 2 * 1.48
≈ 2.96 radians

To convert radians to degrees, we use the conversion factor: 180 degrees / π radians.

HPBW (degrees) = 2.96 * (180 / π)
≈ 169.24 degrees

Therefore, the half power beamwidth of the broadside array is approximately 169.24 degrees.
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