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The equivalent bending moment for the beam having loading as follows is
BM = 300 kNm
SF = 120 kN
Torsional moment = 72 kNm
Use M 25/ Fe 415,
BM = 300 kNm
SF = 120 kN
Torsional moment = 72 kNm
Use M 25/ Fe 415,
b = 400 mm,
d = 450 mm.
d = 450 mm.
Effective cover = 50 mm
- a)396 kNm
- b)408 kNm
- c)300 kNm
- d)372 kNm
Correct answer is option 'A'. Can you explain this answer?
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To determine the equivalent bending moment (BM) for the given beam, we need to consider the bending moment (BM), shear force (SF), and torsional moment (TM) values provided.
Given:
BM = 300 kNm
SF = 120 kN
TM = 72 kNm
The equivalent bending moment (BM) can be calculated using the formula:
BM_eq = BM + SF * d/2 + TM
Where:
BM_eq is the equivalent bending moment
BM is the actual bending moment
SF is the shear force
d is the depth of the beam
TM is the torsional moment
Substituting the given values into the formula:
BM_eq = 300 kNm + 120 kN * 450 mm/2 + 72 kNm
= 300 kNm + 60 kN * 450 mm + 72 kNm
= 300 kNm + 27,000 kNm + 72 kNm
= 27,372 kNm
However, we need to convert the units from kNm to Nm as the given options are in Nm.
1 kN = 1000 N
1 m = 1000 mm
Therefore,
27,372 kNm = 27,372 * 1000 Nm
= 27,372,000 Nm
Comparing this value with the given options:
a) 396 kNm = 396,000 Nm
b) 408 kNm = 408,000 Nm
c) 300 kNm = 300,000 Nm
d) 372 kNm = 372,000 Nm
None of the given options match the calculated value of 27,372,000 Nm. Therefore, none of the options are correct.
It seems there may be an error in the options provided, as none of them match the calculated value.
Given:
BM = 300 kNm
SF = 120 kN
TM = 72 kNm
The equivalent bending moment (BM) can be calculated using the formula:
BM_eq = BM + SF * d/2 + TM
Where:
BM_eq is the equivalent bending moment
BM is the actual bending moment
SF is the shear force
d is the depth of the beam
TM is the torsional moment
Substituting the given values into the formula:
BM_eq = 300 kNm + 120 kN * 450 mm/2 + 72 kNm
= 300 kNm + 60 kN * 450 mm + 72 kNm
= 300 kNm + 27,000 kNm + 72 kNm
= 27,372 kNm
However, we need to convert the units from kNm to Nm as the given options are in Nm.
1 kN = 1000 N
1 m = 1000 mm
Therefore,
27,372 kNm = 27,372 * 1000 Nm
= 27,372,000 Nm
Comparing this value with the given options:
a) 396 kNm = 396,000 Nm
b) 408 kNm = 408,000 Nm
c) 300 kNm = 300,000 Nm
d) 372 kNm = 372,000 Nm
None of the given options match the calculated value of 27,372,000 Nm. Therefore, none of the options are correct.
It seems there may be an error in the options provided, as none of them match the calculated value.
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The equivalent bending momentfor the beam having loading asfollows isBM = 300 kNmSF = 120 kNTorsional moment = 72 kNmUse M 25/ Fe 415,b = 400 mm,d = 450 mm.Effective cover = 50mma)396 kNmb)408 kNmc)300 kNmd)372 kNmCorrect answer is option 'A'. Can you explain this answer?
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