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A part of 2000 is lent at 6% per annum and rest sum is lent at 8% per annum.If total interest earned after 4 years is 500. Then the sum lent at 8%.
  • a)
    250
  • b)
    350
  • c)
    450
  • d)
    550
Correct answer is option 'A'. Can you explain this answer?
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A part of 2000 is lent at 6% per annum and rest sum is lent at 8% per ...
Answer –a) 250 Solution: Let sum lent at 8% is X 500 = X*(8/100)*4 + (2000-X)*(6/100)*4
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A part of 2000 is lent at 6% per annum and rest sum is lent at 8% per ...
Option A. 250  
Here let's take the part of 2000 lent at 6% PA as 'x' and the 'rest' sum lent at 8% PA as (2000-x). As both derivations are for 1 year (PA) let's calculate the interest earned for 1 year. 
Total Int earned for 4 years = 500; Hence Interest earned for one year = 125.  
Now, we need to find (2000-x). 
From the given information let's take the below. 
x*(6/100)+(200-x)*8/100 =125  
x*6+16000-x*8/100=125 
6x+16000-8x=125*100 
6x-8x=12500-16000 
-2x=-3500 
x=1750 
Now The sum lent at 8% is (2000-x) 
The solution is (2000-1750) = 250 
Hence option A. 250 


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