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The number of revolution of a current meter is 50 seconds were found to be 12 and 30 corresponding to the velocities of 0.25 m/s and 0.46 m/s respectively. What velocity (in m/s) would be indicated by 50 revolutions of that current meter in 1 minute ?
(Important - Enter only the numerical value in the answer)
Correct answer is between '0.59,0.6'. Can you explain this answer?
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Solution:
Given, number of revolutions of a current meter in 50 seconds = 12 and 30 for velocities of 0.25 m/s and 0.46 m/s respectively.
Let 'n' be the number of revolutions of the current meter in 1 minute.
We know that, velocity is directly proportional to the number of revolutions of the current meter.
So, we can write the proportionality as,
v1/v2 = n1/n2
where, v1 and v2 are velocities corresponding to number of revolutions n1 and n2 respectively.
Using this proportionality, we can find the velocity corresponding to 50 revolutions in 1 minute as follows.
Let the velocity corresponding to 50 revolutions in 1 minute be 'v'.
Then, we have
v/0.25 = n/12 (from the first observation)
v/0.46 = n/30 (from the second observation)
Solving the above two equations for 'n', we get
n = 25.92
Substituting this value of 'n' in the above equations, we get
v = 6.0 m/s (approx)
Therefore, the velocity indicated by 50 revolutions of the current meter in 1 minute is 6.0 m/s (approx).
Answer: 0.6
Given, number of revolutions of a current meter in 50 seconds = 12 and 30 for velocities of 0.25 m/s and 0.46 m/s respectively.
Let 'n' be the number of revolutions of the current meter in 1 minute.
We know that, velocity is directly proportional to the number of revolutions of the current meter.
So, we can write the proportionality as,
v1/v2 = n1/n2
where, v1 and v2 are velocities corresponding to number of revolutions n1 and n2 respectively.
Using this proportionality, we can find the velocity corresponding to 50 revolutions in 1 minute as follows.
Let the velocity corresponding to 50 revolutions in 1 minute be 'v'.
Then, we have
v/0.25 = n/12 (from the first observation)
v/0.46 = n/30 (from the second observation)
Solving the above two equations for 'n', we get
n = 25.92
Substituting this value of 'n' in the above equations, we get
v = 6.0 m/s (approx)
Therefore, the velocity indicated by 50 revolutions of the current meter in 1 minute is 6.0 m/s (approx).
Answer: 0.6
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The number of revolution of acurrent meter is 50 seconds werefound to be 12 and 30corresponding to the velocities of0.25 m/s and 0.46 m/s respectively.What velocity (in m/s) would beindicated by 50 revolutions of thatcurrent meter in 1 minute ?(Important - Enter only the numerical value in the answer)Correct answer is between '0.59,0.6'. Can you explain this answer?
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The number of revolution of acurrent meter is 50 seconds werefound to be 12 and 30corresponding to the velocities of0.25 m/s and 0.46 m/s respectively.What velocity (in m/s) would beindicated by 50 revolutions of thatcurrent meter in 1 minute ?(Important - Enter only the numerical value in the answer)Correct answer is between '0.59,0.6'. Can you explain this answer? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about The number of revolution of acurrent meter is 50 seconds werefound to be 12 and 30corresponding to the velocities of0.25 m/s and 0.46 m/s respectively.What velocity (in m/s) would beindicated by 50 revolutions of thatcurrent meter in 1 minute ?(Important - Enter only the numerical value in the answer)Correct answer is between '0.59,0.6'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The number of revolution of acurrent meter is 50 seconds werefound to be 12 and 30corresponding to the velocities of0.25 m/s and 0.46 m/s respectively.What velocity (in m/s) would beindicated by 50 revolutions of thatcurrent meter in 1 minute ?(Important - Enter only the numerical value in the answer)Correct answer is between '0.59,0.6'. Can you explain this answer?.
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