X and Y are two volatile liquids with molar weights of 10 g molandndash;1 and 40 g molandndash;1 respectively. Two cotton plugs, one soaked in X and the other soaked in Y, are simultaneously placed at the ends of a tube of length L = 24 cm, as shown in the figure. The tube is filled with an inert gas at 1 atmosphere pressure and a temperature of 300 K. Vapours of X and Y react to form a product which is firstobserved at a distance d cm from the plug soaked in X. Take X and Y to have equal molecular diameters and assume ideal behaviour for the inert gas and the two vapours.Q. The experimental value of d is found to be smaller than the estimate obtained using Grahamandrsquo;s law. This is due to (JEE Adv. 2014)a)Larger mean free path for X as compared to that of Yb)Larger mean free path for Y as compared to that of Xc)Increased collision frequency of Y with the inert gas as compared to that of X with the inert gasd)Increased collision frequency of X with the inert gas as compared to that of Y with the inert gasCorrect answer is option 'D'. Can you explain this answer?

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X and Y are two volatile liquids with molar weights of 10 g mol^–1 and 40 g mol^–1 respectively. Two cotton plugs, one soaked in X and the other soaked in Y, are simultaneously placed at the ends of a tube of length L = 24 cm, as shown in the figure. The tube is filled with an inert gas at 1 atmosphere pressure and a temperature of 300 K. Vapours of X and Y react to form a product which is first
observed at a distance d cm from the plug soaked in X. Take X and Y to have equal molecular diameters and assume ideal behaviour for the inert gas and the two vapours.

Q. The experimental value of d is found to be smaller than the estimate obtained using Graham’s law. This is due to (JEE Adv. 2014)

a)
Larger mean free path for X as compared to that of Y
b)
Larger mean free path for Y as compared to that of X
c)
Increased collision frequency of Y with the inert gas as compared to that of X with the inert gas
d)
Increased collision frequency of X with the inert gas as compared to that of Y with the inert gas

Correct answer is option 'D'. Can you explain this answer?

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X and Y are two volatile liquids with molar weights of 10 g mol–...

The general formula of mean free path (λ) is

(d = diameter of molecule, p = pressure inside the vessel) Since d and p are same for both gases, ideally their l are same. Hence it must be the higher drift speed of X due to which it is facing more collisions per second with the inert gas in comparison to gas Y. Hence X faces more resistance from inert gas than Y and hence covers lesser distance than that predicted by Graham’s law.

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X and Y are two volatile liquids with molar weights of 10 g mol–1 and 40 g mol–1 respectively. Two cotton plugs, one soaked in X and the other soaked in Y, are simultaneously placed at the ends of a tube of length L = 24 cm, as shown in the figure. The tube is filled with an inert gas at 1 atmosphere pressure and a temperature of 300 K. Vapours of X and Y react to form a product which is firstobserved at a distance d cm from the plug soaked in X. Take X and Y to have equal molecular diameters and assume ideal behaviour for the inert gas and the two vapours.Q. The experimental value of d is found to be smaller than the estimate obtained using Graham’s law. This is due to (JEE Adv. 2014)a)Larger mean free path for X as compared to that of Yb)Larger mean free path for Y as compared to that of Xc)Increased collision frequency of Y with the inert gas as compared to that of X with the inert gasd)Increased collision frequency of X with the inert gas as compared to that of Y with the inert gasCorrect answer is option 'D'. Can you explain this answer?

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X and Y are two volatile liquids with molar weights of 10 g mol–1 and 40 g mol–1 respectively. Two cotton plugs, one soaked in X and the other soaked in Y, are simultaneously placed at the ends of a tube of length L = 24 cm, as shown in the figure. The tube is filled with an inert gas at 1 atmosphere pressure and a temperature of 300 K. Vapours of X and Y react to form a product which is firstobserved at a distance d cm from the plug soaked in X. Take X and Y to have equal molecular diameters and assume ideal behaviour for the inert gas and the two vapours.Q. The experimental value of d is found to be smaller than the estimate obtained using Graham’s law. This is due to (JEE Adv. 2014)a)Larger mean free path for X as compared to that of Yb)Larger mean free path for Y as compared to that of Xc)Increased collision frequency of Y with the inert gas as compared to that of X with the inert gasd)Increased collision frequency of X with the inert gas as compared to that of Y with the inert gasCorrect answer is option 'D'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about X and Y are two volatile liquids with molar weights of 10 g mol–1 and 40 g mol–1 respectively. Two cotton plugs, one soaked in X and the other soaked in Y, are simultaneously placed at the ends of a tube of length L = 24 cm, as shown in the figure. The tube is filled with an inert gas at 1 atmosphere pressure and a temperature of 300 K. Vapours of X and Y react to form a product which is firstobserved at a distance d cm from the plug soaked in X. Take X and Y to have equal molecular diameters and assume ideal behaviour for the inert gas and the two vapours.Q. The experimental value of d is found to be smaller than the estimate obtained using Graham’s law. This is due to (JEE Adv. 2014)a)Larger mean free path for X as compared to that of Yb)Larger mean free path for Y as compared to that of Xc)Increased collision frequency of Y with the inert gas as compared to that of X with the inert gasd)Increased collision frequency of X with the inert gas as compared to that of Y with the inert gasCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for X and Y are two volatile liquids with molar weights of 10 g mol–1 and 40 g mol–1 respectively. Two cotton plugs, one soaked in X and the other soaked in Y, are simultaneously placed at the ends of a tube of length L = 24 cm, as shown in the figure. The tube is filled with an inert gas at 1 atmosphere pressure and a temperature of 300 K. Vapours of X and Y react to form a product which is firstobserved at a distance d cm from the plug soaked in X. Take X and Y to have equal molecular diameters and assume ideal behaviour for the inert gas and the two vapours.Q. The experimental value of d is found to be smaller than the estimate obtained using Graham’s law. This is due to (JEE Adv. 2014)a)Larger mean free path for X as compared to that of Yb)Larger mean free path for Y as compared to that of Xc)Increased collision frequency of Y with the inert gas as compared to that of X with the inert gasd)Increased collision frequency of X with the inert gas as compared to that of Y with the inert gasCorrect answer is option 'D'. Can you explain this answer?.

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Here you can find the meaning of X and Y are two volatile liquids with molar weights of 10 g mol–1 and 40 g mol–1 respectively. Two cotton plugs, one soaked in X and the other soaked in Y, are simultaneously placed at the ends of a tube of length L = 24 cm, as shown in the figure. The tube is filled with an inert gas at 1 atmosphere pressure and a temperature of 300 K. Vapours of X and Y react to form a product which is firstobserved at a distance d cm from the plug soaked in X. Take X and Y to have equal molecular diameters and assume ideal behaviour for the inert gas and the two vapours.Q. The experimental value of d is found to be smaller than the estimate obtained using Graham’s law. This is due to (JEE Adv. 2014)a)Larger mean free path for X as compared to that of Yb)Larger mean free path for Y as compared to that of Xc)Increased collision frequency of Y with the inert gas as compared to that of X with the inert gasd)Increased collision frequency of X with the inert gas as compared to that of Y with the inert gasCorrect answer is option 'D'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of X and Y are two volatile liquids with molar weights of 10 g mol–1 and 40 g mol–1 respectively. Two cotton plugs, one soaked in X and the other soaked in Y, are simultaneously placed at the ends of a tube of length L = 24 cm, as shown in the figure. The tube is filled with an inert gas at 1 atmosphere pressure and a temperature of 300 K. Vapours of X and Y react to form a product which is firstobserved at a distance d cm from the plug soaked in X. Take X and Y to have equal molecular diameters and assume ideal behaviour for the inert gas and the two vapours.Q. The experimental value of d is found to be smaller than the estimate obtained using Graham’s law. This is due to (JEE Adv. 2014)a)Larger mean free path for X as compared to that of Yb)Larger mean free path for Y as compared to that of Xc)Increased collision frequency of Y with the inert gas as compared to that of X with the inert gasd)Increased collision frequency of X with the inert gas as compared to that of Y with the inert gasCorrect answer is option 'D'. Can you explain this answer?, a detailed solution for X and Y are two volatile liquids with molar weights of 10 g mol–1 and 40 g mol–1 respectively. Two cotton plugs, one soaked in X and the other soaked in Y, are simultaneously placed at the ends of a tube of length L = 24 cm, as shown in the figure. The tube is filled with an inert gas at 1 atmosphere pressure and a temperature of 300 K. Vapours of X and Y react to form a product which is firstobserved at a distance d cm from the plug soaked in X. Take X and Y to have equal molecular diameters and assume ideal behaviour for the inert gas and the two vapours.Q. The experimental value of d is found to be smaller than the estimate obtained using Graham’s law. This is due to (JEE Adv. 2014)a)Larger mean free path for X as compared to that of Yb)Larger mean free path for Y as compared to that of Xc)Increased collision frequency of Y with the inert gas as compared to that of X with the inert gasd)Increased collision frequency of X with the inert gas as compared to that of Y with the inert gasCorrect answer is option 'D'. Can you explain this answer? has been provided alongside types of X and Y are two volatile liquids with molar weights of 10 g mol–1 and 40 g mol–1 respectively. Two cotton plugs, one soaked in X and the other soaked in Y, are simultaneously placed at the ends of a tube of length L = 24 cm, as shown in the figure. The tube is filled with an inert gas at 1 atmosphere pressure and a temperature of 300 K. Vapours of X and Y react to form a product which is firstobserved at a distance d cm from the plug soaked in X. Take X and Y to have equal molecular diameters and assume ideal behaviour for the inert gas and the two vapours.Q. The experimental value of d is found to be smaller than the estimate obtained using Graham’s law. This is due to (JEE Adv. 2014)a)Larger mean free path for X as compared to that of Yb)Larger mean free path for Y as compared to that of Xc)Increased collision frequency of Y with the inert gas as compared to that of X with the inert gasd)Increased collision frequency of X with the inert gas as compared to that of Y with the inert gasCorrect answer is option 'D'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice X and Y are two volatile liquids with molar weights of 10 g mol–1 and 40 g mol–1 respectively. Two cotton plugs, one soaked in X and the other soaked in Y, are simultaneously placed at the ends of a tube of length L = 24 cm, as shown in the figure. The tube is filled with an inert gas at 1 atmosphere pressure and a temperature of 300 K. Vapours of X and Y react to form a product which is firstobserved at a distance d cm from the plug soaked in X. Take X and Y to have equal molecular diameters and assume ideal behaviour for the inert gas and the two vapours.Q. The experimental value of d is found to be smaller than the estimate obtained using Graham’s law. This is due to (JEE Adv. 2014)a)Larger mean free path for X as compared to that of Yb)Larger mean free path for Y as compared to that of Xc)Increased collision frequency of Y with the inert gas as compared to that of X with the inert gasd)Increased collision frequency of X with the inert gas as compared to that of Y with the inert gasCorrect answer is option 'D'. Can you explain this answer? tests, examples and also practice JEE tests.

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