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The mean of five numbers is 30. If one number is excluded, their mean becomes 28. The excluded number is
  • a)
    28
  • b)
    30
  • c)
    35
  • d)
    38
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
The mean of five numbers is 30. If one number is excluded, their mean ...
Mean of 5 numbers = 30
Total sum of 5 numbers = 30 x 5 = 150
After excluded one number
Mean of 4 numbers will be = 28
Total sum of 4 numbers = 4x28=112
Thus, excluded number
= (sum of 5 numbers - sum of 4 numbers)
= 150-112 = 38 
Option (d) is correct.
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Most Upvoted Answer
The mean of five numbers is 30. If one number is excluded, their mean ...
Mean of 5 numbers is 30
Let's assume the five numbers are a, b, c, d, and e.
So, their mean is given by:
(a + b + c + d + e) / 5 = 30

Mean of 4 numbers is 28
If we exclude one number, let's say 'e', the mean of the remaining four numbers will be 28.
So, the sum of the remaining four numbers is given by:
(a + b + c + d) = 28 * 4 = 112

Calculating the excluded number
To calculate the excluded number, we need to find the difference between the sum of the five numbers and the sum of the remaining four numbers.
The excluded number can be found using the equation:
Excluded number = Sum of five numbers - Sum of four numbers
Excluded number = (a + b + c + d + e) - (a + b + c + d)
Excluded number = e

Substituting the given mean values
Now, we substitute the mean values given in the question.
(a + b + c + d + e) / 5 = 30
(a + b + c + d) + e = 30 * 5
112 + e = 150
e = 150 - 112
e = 38

Therefore, the excluded number is 38, which corresponds to option D.
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The mean of five numbers is 30. If one number is excluded, their mean becomes 28. The excluded number isa)28b)30c)35d)38Correct answer is option 'D'. Can you explain this answer?
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