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The ''spin-only'' magnetic moment [in units of Bohr magneton] of Ni2+ in aqueous solution would be (At. No. Ni = 28) –  
[AIEEE-2006]
  • a)
    0
  • b)
    1.73
  • c)
    2.84
  • d)
     4.90
Correct answer is option 'C'. Can you explain this answer?
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The correct answer is option C
In aqueous solution, as aqua is poor ligand so high spin complex forms.
Electronic configuration of Ni=[Ar] 4s23d8
Electronic configuration of Ni2+=[Ar] 4s0 3d8
Ni+2,d8 configuration, have 2 unpaired electrons so the magnetic moment is:
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The ''spin-only'' magnetic moment [in units of Bohr magneton] of Ni2+in aqueous solution would be (At. No. Ni = 28) – [AIEEE-2006]a)0b)1.73c)2.84d)4.90Correct answer is option 'C'. Can you explain this answer? for Class 12 2025 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about The ''spin-only'' magnetic moment [in units of Bohr magneton] of Ni2+in aqueous solution would be (At. No. Ni = 28) – [AIEEE-2006]a)0b)1.73c)2.84d)4.90Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for Class 12 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The ''spin-only'' magnetic moment [in units of Bohr magneton] of Ni2+in aqueous solution would be (At. No. Ni = 28) – [AIEEE-2006]a)0b)1.73c)2.84d)4.90Correct answer is option 'C'. Can you explain this answer?.
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