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In Marshall method of mix design, the course aggregate, fine aggregated, filler and bitumen having respective specific gravities of 2.6, 2.7, 2.65 and 1.02 are mixed in the ratio of 0.55 : 0.346 : 0.48 : 0.056 respectively.
Specific gravity of the mix would be………..
  • a)
    1.75
  • b)
    1.81
  • c)
    1.64
  • d)
    1.79
Correct answer is option 'A'. Can you explain this answer?
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In Marshall method of mix design, the course aggregate, fine aggregate...
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In Marshall method of mix design, the course aggregate, fine aggregate...
To find the specific gravity of the mix, we need to calculate the weighted average of the specific gravities of each component.

The weighted average formula is:
Specific gravity of the mix = (Specific gravity of course aggregate * ratio of course aggregate) + (Specific gravity of fine aggregate * ratio of fine aggregate) + (Specific gravity of filler * ratio of filler) + (Specific gravity of bitumen * ratio of bitumen)

Specific gravity of the mix = (2.6 * 0.55) + (2.7 * 0.346) + (2.65 * 0.48) + (1.02 * 0.056)

Specific gravity of the mix = 1.43 + 0.9342 + 1.272 + 0.05712

Specific gravity of the mix ≈ 3.70432

Therefore, the specific gravity of the mix would be approximately 3.70432.
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In Marshall method of mix design, the course aggregate, fine aggregated, filler and bitumen having respective specific gravities of 2.6, 2.7, 2.65 and 1.02 are mixed in the ratio of 0.55 : 0.346 : 0.48 : 0.056 respectively.Specific gravity of the mix would be………..a)1.75b)1.81c)1.64d)1.79Correct answer is option 'A'. Can you explain this answer?
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