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For a cell reaction involving a two-electron change, thestandard e.m.f. of the cell is found to be 0.295 V at 25ºC. The equilibrium constant of the reaction at 25ºC will be               [2003
  • a)
    29.5 × 10–2
  • b)
    10]
  • c)
    1 × 1010
  • d)
    1 × 10–10
Correct answer is option 'C'. Can you explain this answer?
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For a cell reaction involving a two-electron change, thestandard e.m.f...
The equilibrium constant is related to the standard emf of cell by the expression
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For a cell reaction involving a two-electron change, thestandard e.m.f. of the cell is found to be 0.295 V at 25ºC. The equilibrium constant of the reaction at 25ºC will be [2003a)29.5 × 10–2b)10]c)1 × 1010d)1 × 10–10Correct answer is option 'C'. Can you explain this answer?
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For a cell reaction involving a two-electron change, thestandard e.m.f. of the cell is found to be 0.295 V at 25ºC. The equilibrium constant of the reaction at 25ºC will be [2003a)29.5 × 10–2b)10]c)1 × 1010d)1 × 10–10Correct answer is option 'C'. Can you explain this answer? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about For a cell reaction involving a two-electron change, thestandard e.m.f. of the cell is found to be 0.295 V at 25ºC. The equilibrium constant of the reaction at 25ºC will be [2003a)29.5 × 10–2b)10]c)1 × 1010d)1 × 10–10Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for For a cell reaction involving a two-electron change, thestandard e.m.f. of the cell is found to be 0.295 V at 25ºC. The equilibrium constant of the reaction at 25ºC will be [2003a)29.5 × 10–2b)10]c)1 × 1010d)1 × 10–10Correct answer is option 'C'. Can you explain this answer?.
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