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The equilibrium constant at 298K for a reaction A B<=>C D is 100. If the initial concentration of all the 4 species were 1 M each, then equilibrium concentration of D is (in M) a) 0.818 b) 1.818 c) 1.182 d) 0.182?
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The equilibrium constant at 298K for a reaction A BC D is 100. If the ...
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The equilibrium constant at 298K for a reaction A BC D is 100. If the ...
Explanation:



Given,


Equilibrium constant (K) = 100


Initial concentration of A = 1M


Initial concentration of B = 1M


Initial concentration of C = 1M


Initial concentration of D = 1M


The reaction is: A + BC ⇌ AB + C


Let the equilibrium concentration of D be x M. Then, the equilibrium concentrations of A, B, and C will be (1-x) M, (1-x) M, and x M, respectively.


The equilibrium constant expression for the reaction is: K = [AB][C]/[A][BC]


Substituting the equilibrium concentrations, we get:


K = x/(1-x)^2


Solving for x, we get:


x = K(1-x)^2 = 100(1-x)^2


x = 1.818 M (approx)


Therefore, the equilibrium concentration of D is 1.818 M (option b).

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The equilibrium constant at 298K for a reaction A BC D is 100. If the initial concentration of all the 4 species were 1 M each, then equilibrium concentration of D is (in M) a) 0.818 b) 1.818 c) 1.182 d) 0.182?
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