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The equilibrium constant at 298 K for a reaction A + BC + D is 100. If the initial concentration of all the four species were 1M each, then equilibrium concentration of D (in mol L-1) will be :a)0.182b)0.818c)1.818d)1.182Correct answer is option 'C'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared
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the JEE exam syllabus. Information about The equilibrium constant at 298 K for a reaction A + BC + D is 100. If the initial concentration of all the four species were 1M each, then equilibrium concentration of D (in mol L-1) will be :a)0.182b)0.818c)1.818d)1.182Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam.
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The equilibrium constant at 298 K for a reaction A + BC + D is 100. If the initial concentration of all the four species were 1M each, then equilibrium concentration of D (in mol L-1) will be :a)0.182b)0.818c)1.818d)1.182Correct answer is option 'C'. Can you explain this answer?, a detailed solution for The equilibrium constant at 298 K for a reaction A + BC + D is 100. If the initial concentration of all the four species were 1M each, then equilibrium concentration of D (in mol L-1) will be :a)0.182b)0.818c)1.818d)1.182Correct answer is option 'C'. Can you explain this answer? has been provided alongside types of The equilibrium constant at 298 K for a reaction A + BC + D is 100. If the initial concentration of all the four species were 1M each, then equilibrium concentration of D (in mol L-1) will be :a)0.182b)0.818c)1.818d)1.182Correct answer is option 'C'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice The equilibrium constant at 298 K for a reaction A + BC + D is 100. If the initial concentration of all the four species were 1M each, then equilibrium concentration of D (in mol L-1) will be :a)0.182b)0.818c)1.818d)1.182Correct answer is option 'C'. Can you explain this answer? tests, examples and also practice JEE tests.