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The equilibrium constant at 298 K for a reaction A +B C+D is 100. If the initial concentration of all the four species were 1 M each, then equilibrium concentration of D (in mol L–1) will be :
  • a)
    1.818
  • b)
    1.182
  • c)
    0.182
  • d)
    0.818
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
The equilibrium constant at 298 K for a reaction A +B C+D is 100. If ...
Given,
On solving
a = 0.81
[Δ]At eq = 1 + a = 1 + 0.81 = 1.81
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The equilibrium constant at 298 K for a reaction A +B C+D is 100. If the initial concentration of all the four species were 1 M each, then equilibrium concentration of D (in mol L–1) will be :a)1.818b)1.182c)0.182d)0.818Correct answer is option 'A'. Can you explain this answer?
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The equilibrium constant at 298 K for a reaction A +B C+D is 100. If the initial concentration of all the four species were 1 M each, then equilibrium concentration of D (in mol L–1) will be :a)1.818b)1.182c)0.182d)0.818Correct answer is option 'A'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about The equilibrium constant at 298 K for a reaction A +B C+D is 100. If the initial concentration of all the four species were 1 M each, then equilibrium concentration of D (in mol L–1) will be :a)1.818b)1.182c)0.182d)0.818Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The equilibrium constant at 298 K for a reaction A +B C+D is 100. If the initial concentration of all the four species were 1 M each, then equilibrium concentration of D (in mol L–1) will be :a)1.818b)1.182c)0.182d)0.818Correct answer is option 'A'. Can you explain this answer?.
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