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An examination paper has 150 MCQ’s of 1 mark each, with each equation having 4 choices. Each incorrect answer has -0.25 marks. Suppose 1000 students choose all their answers randomly with uniform probability. The sum total of expected marks obtained by all the students is:a)0b)2550c)7525d)9375Correct answer is option 'D'. Can you explain this answer? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about An examination paper has 150 MCQ’s of 1 mark each, with each equation having 4 choices. Each incorrect answer has -0.25 marks. Suppose 1000 students choose all their answers randomly with uniform probability. The sum total of expected marks obtained by all the students is:a)0b)2550c)7525d)9375Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An examination paper has 150 MCQ’s of 1 mark each, with each equation having 4 choices. Each incorrect answer has -0.25 marks. Suppose 1000 students choose all their answers randomly with uniform probability. The sum total of expected marks obtained by all the students is:a)0b)2550c)7525d)9375Correct answer is option 'D'. Can you explain this answer?.

Solutions for An examination paper has 150 MCQ’s of 1 mark each, with each equation having 4 choices. Each incorrect answer has -0.25 marks. Suppose 1000 students choose all their answers randomly with uniform probability. The sum total of expected marks obtained by all the students is:a)0b)2550c)7525d)9375Correct answer is option 'D'. Can you explain this answer? in English & in Hindi are available as part of our courses for Civil Engineering (CE). Download more important topics, notes, lectures and mock test series for Civil Engineering (CE) Exam by signing up for free.

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