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The value of surface integral over the surface of the paraboloid z = 1 - x2 - y2, z > 0, where 
  • a)
    π
  • b)
  • c)
    π/2
  • d)
    -π/2
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
The value of surface integralover the surface of the paraboloidz = 1 -...
By the stock’s theorem we know that
where C is a closed curve bounded by the surface  
x2 +y2 = 1
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Most Upvoted Answer
The value of surface integralover the surface of the paraboloidz = 1 -...
By the stock’s theorem we know that
where C is a closed curve bounded by the surface  
x2 +y2 = 1
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The value of surface integralover the surface of the paraboloidz = 1 - x2 - y2, z > 0, wherea)πb)-πc)π/2d)-π/2Correct answer is option 'B'. Can you explain this answer?
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