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The emf of a standard cadmium cell is 1.02 V at 300 K. The temperature coefficient of the cell is –5.0 x 10–5 V K–1. The value of ΔH° for the cell is _________ kJ mol-1 (rounded up to two decimal places).
[1 F = 96500 C mol-1]
    Correct answer is between '-201.00,-198.00'. Can you explain this answer?
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    The emf of a standard cadmium cell is 1.02 V at 300 K. The temperature...
    -4.0 x 10^-4 K^-1.

    Explanation:

    The temperature coefficient of a cell is defined as the rate of change of its emf with respect to temperature. Mathematically, it can be expressed as:

    α = (1/E) * (dE/dT)

    where α is the temperature coefficient, E is the emf of the cell, and dE/dT is the rate of change of emf with respect to temperature.

    In this case, the emf of the cadmium cell is given as 1.02 V at 300 K. To find the temperature coefficient, we need to differentiate the emf with respect to temperature:

    dE/dT = -4.0 x 10^-4 V/K

    Substituting the given values in the formula for α, we get:

    α = (1/1.02) * (-4.0 x 10^-4) = -3.92 x 10^-4 K^-1

    Therefore, the temperature coefficient of the cadmium cell is -3.92 x 10^-4 K^-1.
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    The emf of a standard cadmium cell is 1.02 V at 300 K. The temperature coefficient of the cell is –5.0 x 10–5 V K–1. The value of ΔH° for the cell is _________ kJ mol-1 (rounded up to two decimal places).[1 F = 96500 C mol-1]Correct answer is between '-201.00,-198.00'. Can you explain this answer?
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    The emf of a standard cadmium cell is 1.02 V at 300 K. The temperature coefficient of the cell is –5.0 x 10–5 V K–1. The value of ΔH° for the cell is _________ kJ mol-1 (rounded up to two decimal places).[1 F = 96500 C mol-1]Correct answer is between '-201.00,-198.00'. Can you explain this answer? for IIT JAM 2024 is part of IIT JAM preparation. The Question and answers have been prepared according to the IIT JAM exam syllabus. Information about The emf of a standard cadmium cell is 1.02 V at 300 K. The temperature coefficient of the cell is –5.0 x 10–5 V K–1. The value of ΔH° for the cell is _________ kJ mol-1 (rounded up to two decimal places).[1 F = 96500 C mol-1]Correct answer is between '-201.00,-198.00'. Can you explain this answer? covers all topics & solutions for IIT JAM 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The emf of a standard cadmium cell is 1.02 V at 300 K. The temperature coefficient of the cell is –5.0 x 10–5 V K–1. The value of ΔH° for the cell is _________ kJ mol-1 (rounded up to two decimal places).[1 F = 96500 C mol-1]Correct answer is between '-201.00,-198.00'. Can you explain this answer?.
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