The value ofwhere F = (x2 - y2)i + xyj and curve C is the arc of curve y =x3 from (0, 0) to (2, 8) is.... (Correction upto two decimal places)Correct answer is '39.238'. Can you explain this answer?

Question

Answer

The curve C is the curve y=x³ from (0,0) to (2,8) Let x = t, Then y = t3. if

is the position vector of any point (x,y) on c, then

Also interms of t ,

At the point (0,0), t = x=0. At the point (2,8), t=2.

Answer

The curve C is the curve y=x³ from (0,0) to (2,8) Let x = t, Then y = t3. if

is the position vector of any point (x,y) on c, then

Also interms of t ,

At the point (0,0), t = x=0. At the point (2,8), t=2.

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