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In a 100% amplitude modulated signal, the power in the upper sideband when carrier power is to be 100 W and modulation system SSBSC, is
- a)100 W
- b)66 W
- c)50 W
- d)25 W
Correct answer is option 'D'. Can you explain this answer?
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Verified Answer
In a 100% amplitude modulated signal, the power in the upper sideband ...
Modulation index = 100% 
1
1Pc = 100 W
Most Upvoted Answer
In a 100% amplitude modulated signal, the power in the upper sideband ...
Here the power in upper side band is
Pusb = Pc ( m2/4)
given m= 100%=1 and Pc = 100W
so when we substitute the values we get
Pusb = 100 ( 1/4) = 25W .....option d
Pusb = Pc ( m2/4)
given m= 100%=1 and Pc = 100W
so when we substitute the values we get
Pusb = 100 ( 1/4) = 25W .....option d
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Community Answer
In a 100% amplitude modulated signal, the power in the upper sideband ...
To understand the power in the upper sideband of a 100% amplitude modulated signal, let's consider the modulation system and the power calculations.
Modulation System: SSBSC (Single Sideband Suppressed Carrier)
In SSBSC modulation, only one sideband is transmitted while the carrier and the other sideband are suppressed. This modulation technique is efficient in terms of bandwidth utilization.
Power Calculation:
Given:
Carrier Power (Pc) = 100 W
In a 100% amplitude modulated signal, the total power is distributed equally between the carrier and the sidebands.
Total Power (Pt) = Carrier Power + Sideband Power
Since the carrier power is 100 W, the sideband power is also 100 W.
Pt = Pc + Psb
100 W = 100 W + Psb
Psb = 100 W - 100 W
Psb = 0 W
In the case of SSBSC modulation, the carrier is completely suppressed, and therefore, there is no power in the carrier.
The power in the upper sideband is equal to half of the total sideband power.
Power in Upper Sideband (Pusb) = Psb/2
Pusb = 0 W/2 = 0 W
Therefore, the power in the upper sideband is 0 W.
However, it is important to note that in practical systems, there may be some residual power in the suppressed carrier and lower sideband due to imperfect modulation and filtering. But in the ideal case of 100% modulation and perfect filtering, the power in the upper sideband is zero.
Hence, the correct answer is option 'D' - 0 W.
Modulation System: SSBSC (Single Sideband Suppressed Carrier)
In SSBSC modulation, only one sideband is transmitted while the carrier and the other sideband are suppressed. This modulation technique is efficient in terms of bandwidth utilization.
Power Calculation:
Given:
Carrier Power (Pc) = 100 W
In a 100% amplitude modulated signal, the total power is distributed equally between the carrier and the sidebands.
Total Power (Pt) = Carrier Power + Sideband Power
Since the carrier power is 100 W, the sideband power is also 100 W.
Pt = Pc + Psb
100 W = 100 W + Psb
Psb = 100 W - 100 W
Psb = 0 W
In the case of SSBSC modulation, the carrier is completely suppressed, and therefore, there is no power in the carrier.
The power in the upper sideband is equal to half of the total sideband power.
Power in Upper Sideband (Pusb) = Psb/2
Pusb = 0 W/2 = 0 W
Therefore, the power in the upper sideband is 0 W.
However, it is important to note that in practical systems, there may be some residual power in the suppressed carrier and lower sideband due to imperfect modulation and filtering. But in the ideal case of 100% modulation and perfect filtering, the power in the upper sideband is zero.
Hence, the correct answer is option 'D' - 0 W.
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In a 100% amplitude modulated signal, the power in the upper sideband when carrier power is to be 100 W and modulation system SSBSC, isa)100 Wb)66 Wc)50 Wd)25 WCorrect answer is option 'D'. Can you explain this answer?
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